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aalyn [17]
3 years ago
9

Which rational number equals 0 point 3 with bar over 3? Question 2 options: 1) 1 over 5 2) 1 over 3 3) 3 over 10 4) 3 over 5

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
7 0

9514 1404 393

Answer:

 2) 1/3

Step-by-step explanation:

The repeating decimal can be converted to a fraction by multiplying it by 10^n and subtracting the original value. n = number of repeating digits. This process cancels all of the repeating digits, so you can find the equivalent fraction.

  x=0.\overline{3}\\\\10x -x=3.\overline{3}-0.\overline{3}=3\\\\x=\dfrac{3}{9}\\\\0.\overline{3}=\dfrac{1}{3}

_____

Your calculator can help you answer this:

  1/5 = 0.2

  1/3 = 0.333.... (repeating) . . . . the number you're looking for

  3/10 = 0.3

  3/5 = 0.6

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Pyramids A and B are similar. Pyramid A has a height of 8 in., and Pyramid B has a height of 24 in. Pyramid A has a volume of 38
Olenka [21]

Answer:

Step-by-step explanation:

142

5 0
3 years ago
Rationalize the denominator of sqrt -49 over (7 - 2i) - (4 + 9i)
zubka84 [21]
\sqrt{ \frac{-49}{(7-2i)-(4+9i) } } 


This one is quite the deal, but we can begin by distributing the negative on the denominator and getting rid of the parenthesis:

\frac{ \sqrt{-49}}{7-2i-4-9i}

See how the denominator now is more a simplification of like terms, with this I mean that you operate the numbers with an "i" together and the ones that do not have an "i" together as well. Namely, the 7 and the -4, the -2i with the -9i.
Therefore having the result: 

\frac{ \sqrt{-49} }{3-11i}

Now, the \sqrt{-49} must be respresented as an imaginary number, and using the multiplication of radicals, we can simplify it to \sqrt{49}  \sqrt{-1}
This means that we get the result 7i for the numerator.

\frac{7i}{3-11i}

In order to rationalize this fraction even further, we have to remember an identity from the previous algebra classes, namely: x^2 - y^2 =(x+y)(x-y)
The difference of squares allows us to remove the imaginary part of this fraction, leaving us with a real number, hopefully, on the denominator.

\frac{7i (3+11i)}{(3-11i)(3+11i)}

See, all I did there was multiply both numerator and denominator with (3+11i) so I could complete the difference of squares.
See how (3-11i)(3+11i)= 3^2 -(11i)^2 therefore, we can finally write:

\frac{7i(3+11i)}{3^2 - (11i)^2 }

I'll let you take it from here, all you have to do is simplify it further.
The simplification is quite straightforward, the numerator distributed the 7i. Namely the product 7i(3+11i) = 21i+77i^2.
You should know from your classes that i^2 = -1, thefore the numerator simplifies to -77+21i
You can do it as a curious thing, but simplifying yields the result:
\frac{-77+21i}{130}
7 0
4 years ago
Find the quotient 4/15÷1/6
Solnce55 [7]

Answer:

1 3/5

Step-by-step explanation:

4/15÷1/6

Copy dot flip

4/15 * 6/1

24/15

Divide the top and bottom by 3

8/5

Change the improper fraction to a mixed number

5 goes into 8 1 time with 3 left over

1 3/5

4 0
3 years ago
Factor the expression below
Mazyrski [523]

Answer:

(2x² + 5x + 2) = (2x + 1)(x +2)

Step-by-step explanation:

Given expression is (2x² + 5x + 2).

We have to factorize the given expression.

(2x²+ 5x + 2) = 2x² + 4x + x + 2

                     = 2x(x + 2) + 1(x + 2)

                     = (2x + 1)(x + 2)

So the factored form of the given expression will be (2x + 1)(x + 2).

6 0
3 years ago
If f(x) = 2x^2 + 2, find f(5)
zlopas [31]

Well, following the order of PEMDAS, I got choice B. 52

For instance, when you plug in 5 for x, you get F(5)=2(5)^2+2.

Moreover, following PEMDAS, you're supposed to solve what's inside the parenthesis, but since there is no operation going on inside the parenthesis, then you simple move on to the exponent.

In this case, you square the number 5, which gives you F(5)=2(25)+2

After that, you Multiply (letter M in PEMDAS). This results in F(5)=50+2.

Finally, you add them, which results in F=52.


By the way, I noticed a mistake in your work. When multiplying 2 by 5, the answer is 10, not 20.

Anyway, hope this helped! :-)  

8 0
4 years ago
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