Use Moivre Formula to find cube roots of 64(cos219+isin219)
Cubic roots =∛[64(cos219+isin219)] = [64(cos219+isin219)]^(1/3)
= 4[(cos219+isin219)]^(1/3)=4[cos(219)/3+isin219/3)]=
= 1.169 + 3.82 i
What the answer would be is 10 :) hope that u are helped
The manufacturer should advertise 13811 pages for each cartridge if it wants to be correct 99% of the time
z-score is the number of standard deviations from the mean value of the reference population
99%=0.99
The z-value associate with 0.99 is 2.33:
2.33 = (X - 12425) / 595:
X - 12425 = 2.33 * 595
X = (2.33 * 595) + 12425
X = 138111
Therefore, The manufacturer should advertise 13811 pages for each cartridge if it wants to be correct 99% of the time
Learn more about the Manufacturer here
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Answer:(2x+5)(x+5)=0
Step-by-step explanation:
2x^2+15x+25=0
Factorise we have
2x^2+10x+5x+25
(2x^2+10x)+(5x+25)=0
2x(x+5)+5(x+5)=0
(2x+5)(x+5)=0
Answer:
a) Percentage of students scored below 300 is 1.79%.
b) Score puts someone in the 90th percentile is 638.
Step-by-step explanation:
Given : Suppose a student's score on a standardize test to be a continuous random variable whose distribution follows the Normal curve.
(a) If the average test score is 510 with a standard deviation of 100 points.
To find : What percentage of students scored below 300 ?
Solution :
Mean
,
Standard deviation 
Sample mean 
Percentage of students scored below 300 is given by,






Percentage of students scored below 300 is 1.79%.
(b) What score puts someone in the 90th percentile?
90th percentile is such that,

Now, 






Score puts someone in the 90th percentile is 638.