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3 years ago

Which is the most common use for infrared waves?

Physics

2 answers:

IceJOKER [234]3 years ago

5 0

Answer:

To provide Heat

Explanation:

Gradpoint question

Salsk061 [2.6K]3 years ago

4 0

Answer : To provide heat.

Explanation :

Infrared waves are the waves having wavelength 700 nm to 1 mm.

The most common use of infrared waves is "to provide heat" i.e. in heat-sensitive thermal imaging cameras. It is a invisible wave. It can only sensed by a sensation of warmth.

For example :

When an object is hot, It will emit energy in the form of infrared waves.

So, correct option is (b)

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Explain why it is dangerous to touch the live wire when a switch in the<br> mains circuit is open.

Fudgin [204]

Answer: all the energy is rushed in the wires due to the swich turning on when touching it may start a fire or electricute

Explanation:

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4 years ago

The electric potential, when measured at a point equidistant from two particles that have charges equal in magnitude but of oppo

Reika [66]

Answer:

C) equal to zero

Explanation:

Electric potential is calculated by multiplying constant and charge, then dividing it by distance. The location that we want to measure is equidistant from two particles, mean that the distance from both particles is the same(r2=r1). The charges of the particle have equal strength of magnitude but the opposite sign(q2=-q1). The resultant will be:V = kq/r

ΔV= V1 + V2= kq1/r1 + kq2/r2

ΔV= V1 + V2= kq1/r1 + k(-q1)/(r)1

ΔV= kq1/r1 - kq1/r1

ΔV=0

The electric potential equal to zero

4 0

4 years ago

An electron is released from rest at the negative plate of a parallel-plate capacitor. If the distance across the plate is 2.0 m

ddd [48]

Answer:

Velocity of electron will be $1.325\times 10^6m/sec$

Explanation:

We have given distance across the plate d = 2 mm $=2\times 10^{-3}m$

Potential difference V = 6 volt

We know that potential difference at any distance is given by

V = Ed , here V is potential difference, E is electric field and d is distance

So $E=\frac{V}{d}=\frac{6}{2\times 10^{-3}}=3000N/C$

Charge on electron $e=1.6\times 10^{-19}C$

We know that expression of velocity is given by $v=\sqrt{\frac{2qEd}{m_e}}$ , here q is charge on electron, E is electric field and d is distance

So $v=\sqrt{\frac{2\times 1.6\times 10^{-19}\times 3000\times 3000}{9.11\times 10^{-31}}}=1.325\times 10^6m/sec$

8 0

4 years ago

Definition Electromagnetic Wave

lara31 [8.8K]

Explanation:

Definition of electromagnetic wave. : one of the waves that are propagated by simultaneous periodic variations of electric and magnetic field intensity and that include radio waves, infrared, visible light, ultraviolet, X-rays, and gamma rays.

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4 years ago

When you cook a steak, what kind of energy do you increase in the steak?

lina2011 [118]

Answer:

B im pretty sure.

Explanation:

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3 years ago