If a sphere has radius of 13 centimeters what is the volume
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Answer:
The distance of the overpass above the ground is approximately 26.795 ft
Step-by-step explanation:
The parameters given are;
The distance from the overpass the engineer stands before determining the angle of elevation of the overpass from his standing point = 100 ft
The angle of elevation of the overpass as determined by the engineer from 100 ft = 15°
By trigonometric ratios, we have;
The opposite side to the 15° angle of elevation in the above case is the distance of the overpass above the ground
The opposite side to the 15° is the distance of the engineer from the base of the overpass
Therefore;
Tan(15°) the height of the overpass=
length
The distance of the overpass above the ground = 100 × tan (15°) ≈ 26.795 ft.
multiply the ones in bracket by the L
T = 7× L + L × RS
T = 7L + LRS
making S the subject by transferring 7L to the left hand side of the equation.
thus
T - 7L = LRS
dividing through by LR