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sveticcg [70]
3 years ago
8

PLEASE HURRY IM TIMED I WILL GVE BRAINLIEST IF CORRECT

Chemistry
1 answer:
Whitepunk [10]3 years ago
6 0
So basically D,E They do absorb water but the roots mainly do that so I don’t know if you should put that.
Please give me brainliest if I’m correct

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If 0.507J of heat leads to a 0.007 degree C change in water, what mass is present?
Ivanshal [37]

Answer:

17.3 g

Explanation:

<u>Given the following data;</u>

  • Quantity of heat, Q = 0.507 J
  • Temperature = 0.007°C
  • Specific heat capacity of water = 4.2 J/g°C

Mathematically, Heat capacity is given by the formula;

Q = MCT

Where;

  • Q represents the heat capacity or quantity of heat.
  • M represents the mass of an object.
  • C represents the specific heat capacity of water.
  • T represents the temperature.

Making "M" the subject of formula, we have;

Mass, \ m = \frac {Q}{CT}

Substituting the values into the formula, we have;

Mass, \ m = \frac {0.507}{0.007*4.2}

Mass, \ m = \frac {0.507}{0.0294}

<em>Mass, m = 17.3 grams</em>

3 0
3 years ago
If the valence electrons were removed, what would be the ion charge of the element?
Marizza181 [45]
The ion charge of this element, Na would be + 1, as a single valence electron has been removed and transferred to another atom, resulting in an atom with a greater number of protons than electrons, making it positively charged.
3 0
4 years ago
Read 2 more answers
CAN YOU HELP ME WITH THIS?????????????????????????????????????? ????????????????????????????????????????????????????????????????
maria [59]

PV=nRT  

P = 85.0 x 10^3 Pa  

T = 273 + 20 = 293 K  

n = 2.0 moles  

R = 8.314 m3. pa / mol .K  

V = 2.0 x 293 x 8.314 / 85.0x10^3 =  0.195623529 m^3

6 0
3 years ago
I need help cause this teacher won’t stop cursin
sveticcg [70]
The answer to the question is b
6 0
3 years ago
For which δg°rxn = –30.5 kj/mol at 37.0 °c and ph 7.0. calculate the value of δgrxn in a biological cell in which [atp] = 5.0 mm
mario62 [17]
We are given ΔG°rxn = -30.5 kJ/mol for the following reaction:

ATP + H₂O → ADP + HPO₄²⁻

We are given a series of concentrations for each of the species and are asked to find the value of ΔG for the reaction. We can use the following formula:

ΔGrxn = ΔG°rxn + RTlnQ

We can use R = 0.008314 kJ/molK; T = 335.15 K and Q is the reaction quotient which can be found as follows, and be sure to first convert each concentration of mM to M:

Q = [ADP][HPO₄²⁻]/[ATP]
Q= [0.00010][0.005]/[0.005]
Q = 0.0001

Now we can use the above formula to solve for ΔGrxn.

ΔGrxn = -30.5 kJ/mol + (0.008314)(310.15)ln(0.00010)
ΔGrxn = -54.3 kJ/mol

The value of ΔGrxn = -54.3 kJ/mol.
6 0
3 years ago
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