All categories

4 years ago

5 Uses of elements or its Compounds: Oxygen

Chemistry

1 answer:

melisa1 [442]4 years ago

4 0

fresh air for breathing

ability to sustane life

treat peoples breathing problem

energy in automobiles

industriel procces

You might be interested in

What sample size (grams) of Na3PO4 (FW 164.00) known to be 50.00% pure should be used to consume exactly 40.00 mL of 0.1000 M HC

Mkey [24]

Answer:

0.109 g.

Explanation:

Equation of the reaction:

Na3PO4 + 3HCl --> 3NaCl + H3PO4

Number of moles of HCl = molar concentration × volume

= 0.1 × 0.04

= 0.004 mol.

By stoichiometry, 1 mole of Na3PO4 neutralises 3 moles of HCl. Therefore, number of moles of Na3PO4 = 0.004/3

= 0.0013 mol

Mass of Na3PO4 = molar mass × number of moles

= 0.0013 × 164

= 0.219 g

Since 50% of Na3PO4 was present in the sample. Let 100 g be the total mass of the substance

= 0.219 × 50 g/100 g

= 0.109 g.

3 0

4 years ago

Based on the following information, Cl2(g) + 2 e- → 2 Cl-(aq) E° = + 1.36 V Mg2+(aq) + 2 e- → 2 Mg(s) E° = -2.37 V which of the

Alex

Answer:

D) Mg(s)

Explanation:

We are given:

$E^o_{(Cl_2/Cl^-)}= 1.36V\\E^o_{(Mg^{2+}/Mg)}=-2.37V$

The substance having highest positive $E^o$ potential will always get reduced and will undergo reduction reaction. Here, chlorine will undergo reduction reaction will get reduced. Magnesium will undergo oxidation reaction and will get oxidized.

<u>Reducing agents are the species which reduces others and oxidizes itself. Thus, Magnesium will be the strongest reducing agent.</u>

7 0

4 years ago

A) Find the gas speed of ammonia at 25.0 degrees Celsius. ______________

Cloud [144]

a. 661.23 m/s

b. the rate of effusion of Ammonia = 4.5 faster than Silicon tetra bromide

<h3> Further explanation </h3>

Given

T = 25 + 273 = 298 K

Required

a. the gas speed

b. The rate of effusion comparison

Solution

Average velocities of gases can be expressed as root-mean-square averages. (V rms)

$\large {\boxed {\bold {v_ {rms} = \sqrt {\dfrac {3RT} {Mm}}}}$

R = gas constant, T = temperature, Mm = molar mass of the gas particles

From the question

R = 8,314 J / mol K

T = temperature

Mm = molar mass, kg / mol

Molar mass of Ammonia = 17 g/mol = 0.017 kg/mol

$\tt v=\sqrt{\dfrac{3\times 8.314\times 298}{0.017} }=661.23~m/s$

b. the effusion rates of two gases = the square root of the inverse of their molar masses:

$\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{M_2}{M_1} }$

M₁ = molar mass Ammonia NH₃= 17

M₂ = molar mass Silicon tetra bromide SiBr₄= 348

$\rm \dfrac{r_1}{r_2}=\sqrt{\dfrac{348}{17} }=4.5$

the rate of effusion of Ammonia = 4.5 faster than Silicon tetra bromide

3 0

3 years ago

4. Which of these metals is a pure element? Brass Bronze Silver Steel 5. C is the correct chemical symbol for ....... Calcium Ca

Gala2k [10]

Answer:

4) Silver

5) Carbon

6) Oxygen

3 0

3 years ago

Read 2 more answers

Given the reaction:

sineoko [7]

Answer:

B = 6 grams

Explanation:

please make me brainlist answer

4 0

3 years ago