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lorasvet [3.4K]
2 years ago
15

What type of experiments can be carried out to determine the spontaneity of a reaction? Does spontaneity have any relationship t

o the final equilibrium position of the reaction? Explain.
Chemistry
1 answer:
Alexeev081 [22]2 years ago
6 0

Answer:

Following are the responses to this question:

Explanation:

They can measure the spontaneity of the reaction with the form,\Delta G =\Delta H - T \Delta S Substituting the values of \Delta H, T,\ and \  \Delta S in the above expression information mostly on the playfulness of the reaction would be given to us from the expression above. This reaction is spontaneous if the price of \Delta G is negative, and if it is positive the response is not random. At equilibrium, the values of \Delta G, \Delta H, \ and \ \Delta S are 0.

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Anvisha [2.4K]

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I hope it's helpful!

7 0
3 years ago
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What type of bond would occur between carbon (C) and nitrogen (N)
FrozenT [24]

Answer:

covalent

Explanation:

The carbon and the nitrogen very often form bonds in nature, carbon-nitrogen bonds, which are covalent types of bonds. In fact, the bonds between the carbon and nitrogen are one of the most abundant in the biochemistry and the organic chemistry. The bonds between these two can be double bonds, as well as triple bonds. The carbon-nitrogen bonds have the tendency to be strongly polarized toward the nitrogen.

8 0
3 years ago
Which is the limiting reagent in the following reaction given that you start with 15.5 g of Na2S and 12.1 g CuSO4? Reaction: Na2
NemiM [27]

Answer:

CuSO4

Explanation:

Na2S + CuSO4 → Na2SO4 + CuS

The reaction is balanced (same number of elements in each side)

To determine limiting reagent you need to know the moles you have of each.

Molar mass Na2S = 23 * 2 + 32 = 78

Molar mass CuSO4 = 63.5 + 32 + 16 * 4 = 159.5

Na2S mole = 15.5 / 78 = 0.2

CuSO4 mole = 12.1/159.5 = 0.076

*Remember mole = mass / MM

With that information now you have to divide each moles by its respective stoichiometric coefficient

Na2S stoichiometric coefficient : 1

Na2S : 0.2 / 1 = 0.2

CuSO4 stoichiometric coefficient: 1

CuSO4: 0.076 / 1 = 0.076

The smaller number between them its the limiting reagent, CuSO4

8 0
3 years ago
How many moles of S are in 35.4 g of (C3H5)2S?
alexandr402 [8]
<span>0.310 moles First, look up the atomic weights of the elements involved. Atomic weight carbon = 12.0107 Atomic weight hydrogen = 1.00794 Atomic weight sulfur = 32.065 Molar mass (C3H5)2S = 6 * 12.0107 + 10 * 1.00794 + 32.065 = 114.2086 g/mol Moles (C3H5)2S = 35.4 g / 114.2086 g/mol = 0.309959145 mol Since there's just one sulfur atom per (C3H5)2S molecule, the number of moles of sulfur will match the number of moles of (C3H5)2S which is 0.310 when rounded to 3 significant digits.</span>
6 0
3 years ago
Which layer in the diagram was the original layer?
tatiyna
I’m almost sure it’s D but i could be wrong
4 0
2 years ago
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