3 years ago

Help me for my homework

Physics

1 answer:

Serggg [28]3 years ago

5 0

20 cm = bright
40 cm = dim
The longer the wire the bigger the resistance

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An iron bolt of mass 51.5 g hangs from a string 33.3 cm long. The top end of the string is fixed. Without touching it, a magnet

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Answer:

Explanation:

Let magnetic force F acts towards right and the string makes an angle of θ with the vertical in equilibrium .Let T be tension in equilibrium

T cos θ = mg

T sin θ = F

Dividing

Tan θ = F / mg

F = mg Tanθ

= 51.5 x 9.8 x 10⁻³ x 26 / 20.8 Tanθ = 26 / 20.8 )

= 630.875 X 10⁻³ N

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3 years ago

hich muscle fibers are best suited for activities that involve lifting large, heavy objects for a short period of time? cardiac

Temka [501]

Answer:

Dead lifting uses tho muscle fundamentals

Explanation:

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4 years ago

2. If you exert a force of 10.0 N to lift a box a distance of 0.9 m, how much work have you done?

KonstantinChe [14]

<span> force of 10.0 N
</span>
<span>distance of 0.9 m
w=f*d
w=10*0.9
=9.0 j</span>

6 0

3 years ago

Read 2 more answers

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vredina [299]

Answer:

the vertical acceleration is 9.8 m/s,

downward and no horizontal acceleration..

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3 years ago

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An object with a mass of 2.00 kg is placed at the end of a spring, having a spring constant of 180.0 N/m. The spring is then com

s2008m [1.1K]

Answer:

the velocity of the mass is 8.44 m/s

Explanation:

Given;

mass of the object, m = 2 kg

spring constant, k = 180 N/m

extension of the spring, x = 0.89 m

The maximum velocity of the mass is calculated as follows;

By the principle of conservation of energy;

Elastic potential energy = kinetic potential energy

¹/₂kx² = ¹/₂mv²

kx² = mv²

$v^2 = \frac{kx^2}{m} \\\\v = \sqrt{\frac{kx^2}{m} } \\\\v = \sqrt{\frac{180 \times 0.89^2}{2} }\\\\v = 8.44 \ m/s$

Therefore, the velocity of the mass is 8.44 m/s

8 0

3 years ago