The perpendicular line would have a slope of 1/3.
Perpendicular lines have opposite and reciprocal slopes. So first we have to find the slope of the original line. We can do this by solving the equation for y.
5x - 9y = 1
-9y = -5x + 1
y = 5/9x - 1/9
To do the opposite, take the original slope (5/9) and change the sign (-5/9).
To do the reciprocal, take the slope we changed (-5/9) and flip it as a fraction (-9/5).
This gives us a new slope of
Answer:
x = 8
Step-by-step explanation:
well using the theorem we have
![\frac{6}{9}=\frac{x}{12}\\\\\frac{2}{3}=\frac{x}{12}\\\\12[\frac{2}{3}]=12[\frac{x}{12}]\\\\4\cdot 2=x\\\\x=8](https://tex.z-dn.net/?f=%5Cfrac%7B6%7D%7B9%7D%3D%5Cfrac%7Bx%7D%7B12%7D%5C%5C%5C%5C%5Cfrac%7B2%7D%7B3%7D%3D%5Cfrac%7Bx%7D%7B12%7D%5C%5C%5C%5C12%5B%5Cfrac%7B2%7D%7B3%7D%5D%3D12%5B%5Cfrac%7Bx%7D%7B12%7D%5D%5C%5C%5C%5C4%5Ccdot%202%3Dx%5C%5C%5C%5Cx%3D8)
Two lines are perpendicular if and only if the product of their slopes is - 1.
So, you just need to find the slope of each line and find out the product of their slopes.
I will do one example for you.
L1: y = 3x + 5
L2: y = - 3x + 14
L3: y = -x/3 + 14
The slope of a line is the coefficient of the x.
So the slopes are:
L1: slope 3
L2: slope -3
L3: slope -1/3
So now multiply the slopes of each pair of lines:
L1 and L2: 3 * (-3) = - 9 => No, they are not perpendicular
L2 and L3: (-3) * (-1/3) = 1 => No, they are not perpendicular
L1 and L3: (3) * (-1/3) = -1 => Yes, they are penpendicular.
Answer:
I need Help on this one too.
Step-by-step explanation:
