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andrezito [222]
4 years ago
10

A flat rate shipping box is in the shape of a rectangular prism. You estimate that the volume of the box is 350 cubic inches. Yo

u measure the box and find that it has a length of 10 inches, a width of 9 inches, and a height of 4.5 inches. Find the percent error. Round your answer to the nearest tenth of a percent.
Mathematics
1 answer:
Jlenok [28]4 years ago
5 0
 You estimate that the volume of the box is 350 cubic inches. You measure the box and find that it has a length of 10 inches, a width of 9 inches, and a height of 4.5 inches. Find the percent error. Round your answer to the nearest tenth of a percent.
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MariettaO [177]

Answer:

5/7-1/3=8/21

So is 8/21

7 0
3 years ago
Whats the answer to 26.02 x 2.006
finlep [7]

Answer:

52.19612

Step-by-step explanation:

hope this helps

8 0
4 years ago
Exhibit B: A restaurant has tracked the number of meals served at lunch over the last four weeks. The data shows little in terms
Mekhanik [1.2K]

Answer:

Option E is correct.

The expected number of meals expected to be served on Wednesday in week 5 = 74.2

Step-by-step Explanation:

We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.

Week

Day 1 2 3 4 | Total

Sunday 40 35 39 43 | 157

Monday 54 55 51 59 | 219

Tuesday 61 60 65 64 | 250

Wednesday 72 77 78 69 | 296

Thursday 89 80 81 79 | 329

Friday 91 90 99 95 | 375

Saturday 80 82 81 83 | 326

Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952

Total number of meals served at lunch on Wednesdays over the 4 weeks = 296

Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443

Total number of meals expected to be served in week 5 = 490

Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3

Checking the options,

74.3 ≈ 74.2

Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2

Hope this Helps!!!

8 0
3 years ago
Divide using long division (4x^2-2x+7) divided by (x-1)
Julli [10]
The answer is: 4x-3+7/x
8 0
3 years ago
The perimeter of a rectangle is 22 inches. Find the dimensions if its length is 3 inches greater than its width.
MaRussiya [10]

Answer:

Length: 7

Width: 4

Step-by-step explanation:

We can create a system of equations for this problem, where w is the width and l is the length.

The perimeter of a rectangle is twice its length added to twice its width.

2l+2w=22

The length is 3 more than the width:

l = w+3

We can now substitute in w+3 as l in the equation 2l+2w=22.

2(w+3) + 2w = 22

Distribute the first terms:

2w+6+2w=22

Combine like terms:

4w+6=22

Subtract 6 from both sides:

4w=16

Divide both sides by 4:

w = 4

Now we know that w = 4. We can now substitute this inside an equation to find l.

l = w+3\\\\l = 4+3\\\\l=7

Hope this helped!

7 0
4 years ago
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