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2 years ago

12

The experimental probability that Diana will win a game is 3/8. If she plays the game 80 times, approximately how many times sho

uld she expect to win?

1 answer:

castortr0y [4]2 years ago

5 0

Answer:

She should win approximately 30 times.

Step-by-step explanation:

Since the probability of winning is 3/8, we multiply 3/8 with 80 to get 30.

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The library drawer-upon-drawer file that contains information about every book in the library is called the card catalog.

lawyer [7]

The answer would be TRUE i hope this helps :)

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3 years ago

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The weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016

hodyreva [135]

Answer:

Required Probability = 0.97062

Step-by-step explanation:

We are given that the weights of newborn baby boys born at a local hospital are believed to have a normal distribution with a mean weight of 4016 grams and a standard deviation of 532 grams.

Let X = weight of the newborn baby, so X ~ N( $\mu=4016 , \sigma^{2} = 532^{2}$ )

The standard normal z distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

Now, probability that the weight will be less than 5026 grams = P(X < 5026)

P(X < 5026) = P( $\frac{X-\mu}{\sigma}$ < $\frac{5026-4016}{532}$ ) = P(Z < 1.89) = 0.97062

Therefore, the probability that the weight will be less than 5026 grams is 0.97062 .

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3 years ago

Solve by using the quadratic formula: Simplify

larisa [96]

Answer:

-6 - square root 31, -6 + square root 31

8 0

2 years ago

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A cylinder has a height of 13 centimeters and a radius of 4 centimeters. What is its volume? Use ≈ 3.14 and round your answer

Roman55 [17]

Answer:

Volume of a cylinder = 653.12 cm³

Step-by-step explanation:

Volume of a cylinder = πr²h

Where,

Height, h = 13 cm

Radius, r = 4 cm

π = 3.14

Volume of a cylinder = πr²h

= 3.14 × (4cm)² × 13 cm

= 3.14 × 16 cm² × 13 cm

= 653.12 cm³

Volume of a cylinder = 653.12 cm³

4 0

2 years ago

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A particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past

Vadim26 [7]

Answer:

We conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

Step-by-step explanation:

We are given that a particular brand of tires claims that its deluxe tire averages at least 50,000 miles before it needs to be replaced. From past studies of this tire, the standard deviation is known to be 8000.

From the 28 tires surveyed, the mean lifespan was 46,500 miles with a standard deviation of 9800 miles.

<u><em>Let </em></u> $\mu$ <u><em> = average miles for deluxe tires</em></u>

So, Null Hypothesis, $H_0$ : $\mu \geq$ 50,000 miles {means that deluxe tire averages at least 50,000 miles before it needs to be replaced}

Alternate Hypothesis, $H_A$ : $\mu$ < 50,000 miles {means that deluxe tire averages less than 50,000 miles before it needs to be replaced}

The test statistics that will be used here is <u>One-sample z test statistics</u> as we know about population standard deviation;

T.S. = $\frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }$ ~ N(0,1)

where, $\bar X$ = sample mean lifespan = 46,500 miles

$\sigma$ = population standard deviation = 8000 miles

n = sample of tires = 28

So, <u><em>test statistics</em></u> = $\frac{46,500-50,000}{\frac{8000}{\sqrt{28} } }$

= -2.315

The value of the test statistics is -2.315.

Now at 5% significance level, the z table gives critical value of -1.6449 for left-tailed test. Since our test statistics is less than the critical value of z as -2.315 < -1.6449, so we have sufficient evidence to reject our null hypothesis as it will fall in the rejection region due to which we reject our null hypothesis.

Therefore, we conclude that deluxe tire averages less than 50,000 miles before it needs to be replaced which means that the claim is not supported.

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3 years ago