54 volts
Ohms law. E= I x R
Answer:
minimum of 12 bits is required
Explanation:
Full scale range Ef = 5v = L
Resolution 
n = 4 bit
![R_{ADC} = \frac{5}{2^4 -1} = 0.333 VQuartization error is[tex] \epsilon = \frac{1}{2} R_{ADC}](https://tex.z-dn.net/?f=R_%7BADC%7D%20%3D%20%5Cfrac%7B5%7D%7B2%5E4%20-1%7D%20%3D%200.333%20V%3C%2Fp%3E%3Cp%3EQuartization%20error%20%20is%3C%2Fp%3E%3Cp%3E%5Btex%5D%20%5Cepsilon%20%3D%20%5Cfrac%7B1%7D%7B2%7D%20R_%7BADC%7D)
we know if error is less than 0.001 V then we have
Solving for n we get
n = 12
Therefore minimum of 12 bits is required
Answer: Yes, it will be around 40ppm(at steady state)
Explanation:
The above question can be solved by performing material balance of CO in the building. The material balance equation is given by, Rate of change of CO in the building = Rate of inflow of CO into the building - Rate of outflow of CO from the blood
Answer:
the average flow (vph) = 222.69 veh/hr.
The average velocity = 111348 ft/hr.
density = 2 × 10⁻³ veh/ft.
Explanation:
The first thing to do in this particular question is to determine the average velocity.
The average velocity = [ ( 2940 - 2000/30) + ( 3200 - 2300/30) + ( 2400 - 1700/30) + ( 2100 - 1200) + ( 1730 - 600/30) + ( 1000 - 0/30).
The average velocity = [31.33 + 30 + 23.33 + 30 + 37.66 + 33.66]/ 6 = 30.99 ft/sec.
Thus, 30.99 ft/sec × 60 × 60 = 111348 ft/hr.
The next thing to do is to determine the density. therefore, the density = 6/ 3000 = 2 × 10⁻³ veh/ft.
The average flow (vph) = 111348 ft/hr × 2 × 10⁻³ veh/ft. = 222.69 veh/ hr.
Also, the space mean speed (mph) over the 3000 ft length of the lane = 6/ [ 1/31.33 + 1/30 + 1/23.33 + 1/30 + 1/37.66 + 1/33.66] = 6/ 0.1977 = 30.34 ft/sec.
