Since the armature is wave wound, the magnetic flux per pole is 0.0274 Weber.
<u>Given the following data:</u>
- Number of armature conductors = 144 slots
- Number of poles = 4 poles
- Number of parallel paths = 2
To find the magnetic flux per pole:
Mathematically, the emf generated by a DC generator is given by the formula;
×
<u>Where:</u>
- E is the electromotive force in the DC generator.
- Z is the total number of armature conductors.
- N is the speed or armature rotation in r.p.m.
- P is the number of poles.
- A is the number of parallel paths in armature.
First of all, we would determine the total number of armature conductors:
× ×
Z = 864
Substituting the given parameters into the formula, we have;
×
×
<em>Magnetic flux </em><em>=</em><em> 0.0274 Weber.</em>
Therefore, the magnetic flux per pole is 0.0274 Weber.
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Answer:
V = 280.15 V
Explanation:
" The complete question is attached with figure"
Given:
- The capacitance of the capacitor C = 10 nF
- The amount of mass attached to motor m = 4 grams
- The amount of distance it is to be lifted h = 1 cm
- Ignore all other losses in the system
Find:
- The voltage required to lift the mass m through distance h?
Solution:
- The conservation of energy for the entire system is written as:
Work_gravity = U_c
Where,
Work_gravity: Work done by gravity on mass m
U_c: The amount of energy stored in a capacitor
m*g*h = 0.5*C*V^2
V^2 = 2*m*g*h / C
V = sqrt ( 2*m*g*h / C )
Plug in the values:
V = sqrt ( 2*0.004*9.81*0.01 / 10*10^-9 )
V = sqrt ( 78,480)
V = 28.15 V
Answer:
Actualmente estoy trabajando en una pregunta diferente en este momento.
Explanation:
Actualmente estoy trabajando en una pregunta diferente en este momento.