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3 years ago

8

How could you prove that a rock layer is from the precambrian without using radioactive testing?

1 answer:

noname [10]3 years ago

5 0

You could do this by 1. Looking at what type and from what age the rocks above it are from, and secondly by comparing it with other types of rock that originate from that period.

Hope this helps.

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Blue litmus papaer does not change color in the presence of an acid. true or false

Masja [62]

False. It is used to show the Ph of something.

4 0

3 years ago

Read 2 more answers

A mixture of 1.20 mols He, 2.40 mols Ne, 4.80 mols Kr, and 0.60 mols Ar has a total pressure of 600.0 mm Hg. What is the partial

Juliette [100K]

Answer: The partial pressure of the Kr is 320 mm Hg.

Explanation:

According to Raoult's Law , the partial pressure of each component in the solution is equal to the total pressure multiplied by its mole fraction. It is mathematically expressed as

$p_A=x_A\times P_{total}$

where, $p_A$ = partial pressure of component A

$x_A$ = mole fraction of A

$P_{total}$ = total pressure

mole fraction of Krypton = $\frac{\text {Moles of Kr}}{\text {total moles}}=\frac{4.80}{1.20+2.40+4.80+0.60}=0.53$

$p_{Kr}=0.53\times 600mmHg=320mmHg$

Thus partial pressure of the Kr is 320 mm Hg

8 0

3 years ago

Suppose you were doing the experiment with a 50 mL syringe. How many mL would you pull the plunger for each reading?

goldfiish [28.3K]

50 mL would be the answer

5 0

3 years ago

At 517 mm Hg and 24 °C, a sample of gas occuples a volume of 95 ml. The gas is transferred to a 225-ml flask and the temperature

vodomira [7]

Answer:

$P_2=194.78mmHg$

Explanation:

Hello,

In this case, we employ the combined ideal gas law in order to understand the volume-gas-pressure behavior as shown below:

$\frac{P_1V_1}{T_1}= \frac{P_2V_2}{T_2}$

Hence, solving for the final pressure P2, we obtain (do not forget temperature must be absolute):

$P_2=\frac{P_1V_1T_2}{V_2T_1}=\frac{517mmHg*95mL*(-8.0+273.15)K}{(24+273.15)K*225mL}\\ \\P_2=194.78mmHg$

Best regards.

7 0

4 years ago

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The law of converservation of mass states of the mass to the reacant is

olganol [36]

Answer:

the same as the products.

Explanation:

Law of conservation of mass states that the mass of the reactant is always the same as the products since they are not lost nor gained.

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3 years ago