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Akimi4 [234]
3 years ago
15

Based on the balanced equation: 2 K + Cl2 --> 2KCl what is the mole ratio of K to KCl

Chemistry
1 answer:
yawa3891 [41]3 years ago
6 0

Answer:

2 : 2

Explanation:

The balanced chemical equation is given as:

            2K   +     Cl₂   →    2KCl

From the balanced reaction equation, we can conclude that;

  • 2 moles of K will react with 1 mole of Cl₂
  • 2 moles of K will produce 2 moles of KCl
  • 1 mole of Cl₂ will produce 2 moles of KCl

Therefore, the mole ratio is 2:2 or 1:1 in the simplest form.

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The law of conservation of mass states that the mass of a system must remain constant everytime, it can neither be created or destroyed. This means the number of atoms of each element on reactant side must equal the number of atoms of each element on product side.

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Sr is an alkaline earth metal which has 2 valence electrons that when both are lost it has an oxidation state of +2. Since we know the hydroxide ion has a charge of -1, -_{OH}, Then two -_{OH} are needed to form compound, hence we have SrOH_2

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The oxidation state of zirconium is +1 since it is stated that we have zirconium(I). Converserly, perchlorate has a -1 charge which further proves that zirconium has a +1 oxidation state

The product would have a strontium diperchlorate because we know from earlier that Sr has a +2 oxidation state, and we would also have ZrOH because Zr has a +1 oxidation state and -_{OH} has a -1 charge

The unbalanced equation with all chemicals formulas would be

SrOH_2_(s) + ZrClO^{-} _4(aq) ==> Sr(ClO^{-} _4)_2(aq) + ZrOH(aq)

Using the law of conservation of mass, it is clear that there is 1 molecule of ClO^{-} _4 on reactant side as compared to 2 molecules of ClO^{-} _4 on product side. On the other hand, the are 2 molecules of -_{OH} on reactant side and 1 molecule of  -_{OH} on product side. To balance we add a coefficient of 2 on ZrClO_4 and a coefficient of 2 on ZrOH,

SrOH_2_(s) + 2ZrClO_4_(aq) ==> Sr(ClO_4)_2_(aq) + 2ZrOH(aq).

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