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3 years ago

Two substances in a mixture differ in density and particle size. These properties can be used to

1 answer:

4 0

I think the best answer from the choices listed above is option 1. Two substances in a mixture differ in density and particle size. These properties can be used to separate the substances. These properties can be manipulated in order to have a better separation between the two substances.

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Can someone help me with these two questions?

guapka [62]

Answer:

Explanation:

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3 years ago

The ____ contains the highest concentration of ozone.

ad-work [718]

C. The stratosphere. About 90% of the ozone is in the stratosphere which begins about 8 miles above the Earth's surface.

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4 years ago

Read 2 more answers

The true absorbance for a 1.0 x 10 −5 M solution is 0.7526. If the percentage stray light for a spectrophotometer is 0.56%, calc

Korvikt [17]

Answer:

The percentage deviation is $\Delta M = 1.87$ %

Explanation:

From the question we are told that

The concentration is of the solution is $C = 1.0*10^{-5} M$

The true absorbance A = 0.7526

The percentage of transmittance due to stray light $z = 0.56$ % $=\frac{0.56}{100} = 0.0056$

Generally Absorbance is mathematically represented as

$A = -log T$

Where T is the percentage of true transmittance

Substituting value

$0.7526 = - log T$

$T = 10^{-0.7526}$

$= 0.177$

$= 17.7$ %

The Apparent absorbance is mathematically represented

$A_p = -log (T +z)$

Substituting values

$A_p = -log(0.177 + 0.0056)$

$= -log(0.1826)$

= 0.7385

The percentage by which apparent absorbance deviates from known absorbance is mathematically evaluated as

$\Delta A = \frac{A -A_p}{A} * \frac{100}{1}$

$= \frac{0.7526 - 0.7385}{0.7526} * \frac{100}{1}$

$\Delta A = 1.87$ %

Since Absorbance varies directly with concentration the percentage deviation of the apparent concentration from know concentration is

$\Delta M = 1.87$ %

6 0

4 years ago

A 2.5 g sample of french fries is placed in a calorimeter with 500.0 g of water at an initial temperature of 21 °C. After combus

SIZIF [17.4K]

Q=m°CΔT
=(500g) x (1 cal/g.°C) x (48°C-21°C) = 13500 cal
13500 cal / 1000 = 13.5 kcal

"What is the caloric value (kcal/g) of the french fries?"
13.5 kcal/ 2.5 g = 5.4 kcal/g

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4 years ago

Mendeleev's periodic table of elements was created in 1901. O A. True O B. False

LiRa [457]

B. False
It was created in 1869

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3 years ago