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3 years ago

15

Why are some forms of speech not protected by the First Amendment?

2 answers:

Ivanshal [37]3 years ago

8 0

Answer:

because they could cause physical harm to others

Explanation:

Took the test..

alexdok [17]3 years ago

5 0

Answer:

because they could cause harm to others

Explanation:

The "First Amendment" gives people the right to freedom of: <em>religion, expression, press and assembly. </em>However, the government has the right to censor one's speech<u><em> if it could cause harm to others.</em></u> Such speech falls under "unprotected category." This category includes the following: <em>Defamation, Perjury, Blackmail, Plagiarism, True Threats, Child P.ornography, Obscenity, Solicitations to Commit Crime, Fighting Words, Incitement of Imminent Lawless Action.</em> These forms of speeches are meant to harm other people, thus, they are not protected by the First Amendment.

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A heat pump has a coefficient of performance that is 60% of the Carnot heat pump coefficient of performance. The heat pump is us

Nataliya [291]

Answer:

$T_C$ =118.8 K= 154.2°C

Explanation:

COP_max of carnot heat pump= $\frac{T_{H} }{T_{H}-T_{C} }$

where T_H and T_C are temperatures of hot and cold reservoirs

Also COP= $\frac{Q_H}{W}$

in the question $COP= \frac{60}{100} \times COP_{max}$

⇒ $\frac{Q_H}{W} =\frac{60}{100}\times\frac{T_H}{T_H-T_C}$

heat is added directly to be as efficient as via heat pump

$Q_H= W$

and T_H= 24° C= 297 K

$1=\frac{60}{100}\times \frac{297}{297-T_C}$

on calculating the above equation we get

$T_C$ =118.8 K

the outdoor temperature for efficient addition of heat to interior of home

$T_C$ =118.8 K= 154.2°C

6 0

3 years ago

Speedy Sue, driving at 34.0 m/s, enters a one-lane tunnel. She then observes a slow-moving van 160 m ahead traveling at 5.20 m/s

Zielflug [23.3K]

Answer:

there will be collision

Explanation:

$v_{s}$ = speed of sue = 34 m/s

$v_{v}$ = speed of van = 5.20 m/s

$v_{sv}$ = speed of sue relative to van = $v_{s} - v_{v}$ = 34 - 5.20 = 28.8 m/s

$d_{s}$ = stopping distance after brakes are applied

$D$ = distance between sue and van = 160 m

$v_{f}$ = final speed of sue = 0 m/s

$a$ = acceleration = - 1.80 m/s²

Using the kinematics equation

$v_{f}^{2} = v_{o}^{2} + 2 a d_{s}$

$0^{2} = 28.8^{2} + 2 (1.80) d_{s}$

$d_{s} = 230.4$ m

Since $d_{s} < D$

hence there will be collision

7 0

3 years ago

What is kinetic energy?

Naya [18.7K]

kinetic energy is Movement energy

think of it like the Xbox Kinect

3 0

3 years ago

Read 2 more answers

Afootball of mass 550g is at rest on the ground the football is kicked with a force of 108 newton the footballers boot is in con

d1i1m1o1n [39]

If "0.3 minute" is correct, then it's 9,543,272 Joules.

If it's supposed to say "0.3 SECOND", then the KE is 2,651 Joules.

6 0

3 years ago

Four blocks of weights are required using which any body whose weight is between 1kg and 40 kg can be weighed. Find the four wei

Vikentia [17]

Answer:

The weights are 1 kg, 3kg, 9kg and 27kg.

Explanation:

The weights are 1 kg, 3kg, 9kg and 27kg.

1+3+9+27= 40

27+9+3= 39

27+9+3-1=38

27+9+1=37

27+9=36

27+9-1=35

27+9+1-3=34

27+9-3=33

27+9-3-1=32

27+3+1=31

27+3=30

27+3-1=29

27+1=28

27

27-1=26

27+1-3=25

27-3=24

27-3-1=23

27+3+1-9=22

27+3-9=21

27+3-9-1=20

Like this all the weights from 1 to 40 kg can be made using 1,3,9 and 27 kg.

6 0

3 years ago