Ask question

Ask question

All categories

3 years ago

12

What is the answer for this question (4x³)²

2 answers:

antiseptic1488 [7]3 years ago

7 0

16x to the power of 6 <3

Delvig [45]3 years ago

6 0

16x to the power of 6

You might be interested in

A quantity that has only one magnitude

Len [333]

Answer:

scalar quantity

Explanation:

Vector quantities have two characteristics, a magnitude and a direction. Scalar quantities have only a magnitude.

3 0

4 years ago

In what sense did the flappers dressand dance represent a display of freedom

pishuonlain [190]

Answer:

Flappers are symbols of the Thundering Twenties, the social, political disturbance and expanded transoceanic social trade that followed the finish of World War I. Flappers were viewed as reckless for wearing inordinate cosmetics, drinking liquor, smoking cigarettes in broad daylight, driving vehicles and treating sex nonchalantly. They guaranteed that the flappers' dresses were 'close to exposure', 'nervy', 'foolish', and unintelligent.

6 0

3 years ago

A bicycle is traveling north at 5.0 m/s. The mass of the wheel, 2.0 kg, is uniformly distributed along the rim, which has a radi

andreev551 [17]

Answer:2

Explanation:

Given

Velocity of bicycle is 5 m/s towards north

radius of rim $r=20 cm$

mass of rim $m=2 kg$

Angular momentum $\vec{L}=I\cdot \vec{\omega }$

$I=mr^2=2\times 0.2^2=0.08 kg-m^2$

$\omega =\frac{v}{r}=\frac{5}{0.2}=25 rad/s$

$L=0.08\times 25=2kg-m^2/s$

direction of Angular momentum will be towards west

7 0

3 years ago

a body of mass 0.2kg is whirled round a horizontal circle by a string inclined at 30 degrees to the vertical calculate <br /&

Katen [24]

Answer:

a) T = 2.26 N, b) v = 1.68 m / s

Explanation:

We use Newton's second law

Let's set a reference system where the x-axis is radial and the y-axis is vertical, let's decompose the tension of the string

sin 30 = $\frac{T_x}{T}$

cos 30 = $\frac{T_y}{T}$

Tₓ = T sin 30

T_y = T cos 30

Y axis

T_y -W = 0

T cos 30 = mg (1)

X axis

Tₓ = m a

they relate it is centripetal

a = v² / r

we substitute

T sin 30 = m $\frac{v^2}{r}$ (2)

a) we substitute in 1

T = $\frac{mg }{cos 30}$

T = $\frac{ 0.2 \ 9.8}{cos \ 30}$

T = 2.26 N

b) from equation 2

v² = $\frac{T \ sin 30 \ r}{m}$

If we know the length of the string

sin 30 = r / L

r = L sin 30

we substitute

v² = $\frac{ T \ sin 30 \ L \ sin 30}{m}$

v² = $\frac{TL \ sin^2 30}{m}$

For the problem let us take L = 1 m

let's calculate

v = $\sqrt{ \frac{2.26 \ 1 \ sin^230}{0.2} }$

v = 1.68 m / s

8 0

3 years ago

•. Parking orbit is -

notsponge [240]

Answer:

Parking orbit is -

a. The path along which a plane travels

b. Orbit of a polar satellite

c. Orbit of geostationary satellite

d. Orbit of the earth.

Explanation:

7 0

3 years ago

Read 2 more answers