The wavelength of the radiation emitted by the star is 183 nm.
Explanation:
As per Wien's displacement law, the product of emitted wavelength and temperature of the star will be equal to 2.898 × 10⁻³ mK.
So if the wavelength of the emitted radiation by Sun is given as 550 nm, then the temperature of the Sun will be
Then if the temperature of star is said to be 3.5 times hotter than Sun, then the temperature of Star = 3.5×5.27×10³ = 15.81×10³ K.
With this temperature, the wavelength of the emitted radiation can be found as follows:
So, the wavelength of the radiation emitted by the star is 183 nm.
Answer : B. 0 m/s∧2
Now we know that velocity = distance/ time
And acceleration = velocity/time.
From the graph we see that at the time interval 2 secs,the distance travelled is 10 m. Hence the velocity(v1) =10/2 = 5m/s.
From the graph we see that at the time interval 5 secs,the distance travelled is 25 m. Hence the velocity (v2) =25/5 = 5m/s.
Now acceleceration between the time interval of 2 ad 5 secs is calculated as
(v1-v2)/t2-t1 = (5-5)/(5-2) = 0 m/s∧2
The correct answer is good architecture is
Explanation:
P.E=MGH
(1) P.E=5×10(G)×3
= 150 kg m^/s^ ( ^ =sqaure)
(2) P.E=5×10×6
= 300 kg m^/s^
Hope it helps, just remember the formula u can solve any question regarding gravition of earth (P.E=Mgh)
