The change in velocity is +4 m/s to the right (or -4 m/s to the left).
The object's mass is irrelevant.
Answer:
The charge inside the cube is null.
Explanation:
If we apply the gauss theorem with a cubical gaussian surface of the size of the cube:

If we consider than the direction of the electric field is
, we can solve the problem differentiating the integral for each face of the cube:


E₀ is a constant and each surface is equal to each other, so: 
Therefore:


Answer:
I believe the answer is speed up.
Explanation:
this is because when water heats up the molecules move father apart from each other they speed up, eventually causing the water to boll