Answer:
287.30 g of FeCO₃
Solution:
The Balance Chemical Equation is as follow,
FeCl₂ + Na₂CO₃ → FeCO₃ + 2 NaCl
Step 1: Calculate Mass of FeCl₂ as,
Molarity = Moles ÷ Volume
Solving for Moles,
Moles = Molarity × Volume
Putting Values,
Moles = 2 mol.L⁻¹ × 1.24 L
Moles = 2.48 mol
Also,
Moles = Mass ÷ M.Mass
Solving for Mass,
Mass = Moles × M.Mass
Putting Values,
Mass = 2.48 mol × 126.75 g.mol⁻¹
Mass = 314.34 g of FeCl₂
Step 2: Calculate Mass of FeCO₃ formed as,
According to equation,
126.75 g (1 mole) FeCl₂ produces = 115.85 g (1 mole) FeCO₃
So,
314.34 g of FeCl₂ will produce = X g of FeCO₃
Solving for X,
X = (314.34 g × 115.85 g) ÷ 126.75 g
X = 287.30 g of FeCO₃
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The correct answer is option 3. The IUPAC name is Iron(II) sulfide. It is the less stable amorphous form. When this is powdered, it is pyrophoric or it ignites spontaneously in air. It readily reacts with hydrochloric acid producing hydrogen sulfide.
Answer:
The answer to your question is 330 g of CHO
Explanation:
Data
Calories needed = 2200 kcal/day
CHO = 60%
Proteins = 15%
Fats = 25%
Grams of carbohydrates needed = ?
Process
1.- Calculate the number of calories in 60% of 2200 kcal
2200 kcal ---------------- 100%
x --------------- 60%
x = (60 x 2200) / 100
x = 1320 kcal
2.- Calculate the grams of CHO
1 g of CHO ---------------- 4 kcal
x ---------------- 1320 kcal
x = (1320 x 1) / 4
x = 1320/4
x = 330 g of CHO
I think it would be D. atoms because they are very tiny but still take up space
