Answer:
% comp. H = 2.8%, % comp. Cl = 97.2%
Explanation:
HCl mass = mass of H + mass of Cl
HCL mass = 1.00794 + 35.453 = 36.46094
% comp. of H = 1.007694 / 36.46094 x 100 = around 2.8% (2.76376308455)
% comp. of Cl = 35.453 / 36.46094 x 100 = around 97.2% (97.2355622208)
Solution here,
Volume(V)=67.4 L
Pressure(P)=1 atm
Temperature(T)=(0+273)K=273K
Universal gas constant(R)=0.0821 L.atm.mol^-1K^-1
No. of moles(n)=?
Now,
PV=nRT
or, 1×67.4=n×0.0821×273
or, 67.4=22.4n
or, n=67.4/22.4
or, n=3
therefore, required no. of mole is 3.
According to Charles' Law the volume of an ideal gas is directly proportional to its absolute temperature in Kelvin keeping the pressure constant.
V∝ T, P is constant
where V, T and P are volume, temperature and pressure
= 
where V₁, T₁, V₂ and T₂ are initial volume, initial temperature, final volume and final temperature.
Answer:
There are 1.8×1024 atoms in 1.5 mol HCl
Explanation:
