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Ksenya-84 [330]
4 years ago
12

Answer please 98 points also brainliest

Physics
2 answers:
notsponge [240]4 years ago
6 0

Answer:

d.

Explanation:

Look at it this way, when a sponge is saturated it cannot take in any more water. When air (a mixture of gasses) is saturated it cannot take in any more water vapour and water vapour will condense out as liquid water. This is termed the saturation point.

Air is classed usually as a percentage of saturation, dry air being 0% and saturated 100%

However, unlike the sponge ananalogy, 1kg of air will have a different capacity for water vapour depending on its temperature (and pressure). Charts (Psycrometric Charts) are available that allow the degree of saturation to be calculated, usually by determining the dew point (temperature at which 100% saturation occurs) by using a wet bulb thermometer and comparing it with the normal dry bulb temperature.

Yuri [45]4 years ago
5 0

the answer is D) The air in the aquarium is saturated

none of the other answers were realistic AND I took this before so I know the right answer.

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Astronomers can now report that active star formation was going on at a time when the universe was only 20% as old as it is toda
disa [49]

Answer:

First, as you may know, the light travels at a given velocity.

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3 years ago
What is terminal velocity and how is it reached?
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3 years ago
) A coin is tossed 13 times. a) How many different outcomes are possible? 2^8 b) How many different outcomes have exactly 4 head
Svetradugi [14.3K]

Answer:

Explanation:

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b)

3 0
3 years ago
what was the acceleration of the cart with Low fan speed cm/s squared? what was the acceleration of the cart with medium fan spe
ArbitrLikvidat [17]

Explanation:

The attached figure shows data for the cart speed, distance and time.

For low fan speed,

Distance, d = 500 cm

Time, t = 7.4 s

Average velocity,

v=\dfrac{d}{t}\\\\v=\dfrac{500}{7.4}\\\\v=67.56\ cm/s

Acceleration,

a=\dfrac{v}{t}\\\\a=\dfrac{67.56}{7.4}\\\\a=9.12\ cm/s^2

For medium fan speed,

Distance, d = 500 cm

Time, t = 6.4 s

Average velocity,

v=\dfrac{d}{t}\\\\v=\dfrac{500}{6.4}\\\\v=78.12\ cm/s

Acceleration,

a=\dfrac{v}{t}\\\\a=\dfrac{78.12}{6.4}\\\\a=12.2\ cm/s^2

For high fan speed,

Distance, d = 500 cm

Time, t = 5.6 s

Average velocity,

v=\dfrac{d}{t}\\\\v=\dfrac{500}{5.6}\\\\v=89.28\ cm/s

Acceleration,

a=\dfrac{v}{t}\\\\a=\dfrac{89.28}{5.6}\\\\a=15.94\ cm/s^2

Hence, this is the required solution.

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3 years ago
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(c) Due to up thrust
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