3 years ago

Why can't we factor x^2+25?

Mathematics

1 answer:

arlik [135]3 years ago

4 0

Answer:

Explanation: Notice that if x is Real then x2≥0 , so x2+25 has no linear factors with Real coefficients

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Find the exact value of sine [2 cosine Superscript negative 1 Baseline (- StartFraction StartRoot 2 EndRoot/2 EndFraction )] = n

Nady [450]

Answer:

$\frac{3\pi}{2}$ .

Step-by-step explanation:

The given expression is

$2\cos^{-1}\left(-\frac{\sqrt{2}}{2}\right)$

It can be rewritten as

$2\cos^{-1}\left(-\frac{1}{\sqrt{2}}\right)$

$2\left [\pi-\cos^{-1}\left(\frac{1}{\sqrt{2}}\right)\right]$ $[\because \cos^{-1}(-x)=\pi-\cos^{-1}(x), x\in [-1,1]]$

$2\left [\pi-\cos^{-1}\left(\cos \frac{\pi}{4}\right)\right]$

$2\left [\pi-\frac{\pi}{4}\right]$

$2\left [\frac{4\pi-\pi}{4}\right]$

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Hence, the exact value of given expression is $\frac{3\pi}{2}$ .

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3 years ago

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Gre4nikov [31]

12.93
Use inverse operations
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2n + 5 = n - 5<br> Find the number that n is<br> And please explain :)

Archy [21]

Answer:

-10

Step-by-step explanation:

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n200080 [17]

<span>The factors of 18 are 1, 2, 3, 6, 9, 18.</span>

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4 years ago

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Note: Remember to show all of the steps that you use to solve the problem. You can use the comments field to explain your work.

Butoxors [25]

Factor: 20k+50

since you see there is a multiple of 10 you can do…

10(2k+5)

next you look if you can factor anything else as you can see you cannot so…

10(2k+5) is you answer

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3 years ago