Question

11. A car is pulled with a force of 10,000 N. The car's mass is 1267 kg. But, the car covers 394.6 m in 15 seconds.

Answer 1

Answer:

A) a = 7.89 m/s²

B) a = 3.51 m/s²

C) 4.38 m/s²

D) Frictional force

E) F_f = 5552.83 N

Explanation:

A) Formula for Force is;

F = ma

Where;

m is mass

a is acceleration

We are given;

F = 10,000 N

m = 1267 kg

Thus;

10000 = 1267a

a = 10000/1267

a = 7.89 m/s²

B) We are told the car covers 394.6 m in 15 seconds.

Using Newton's third equation equation of motion, we can find the actual acceleration.

s = ut + ½at²

u is zero since the object began from rest.

Thus;

S = ½at²

394.6 = ½ × a × 15²

a = 394.6 × 2/225

a = 3.51 m/s²

C) difference in accelerations = 7.89 - 3.51 = 4.38 m/s²

D) The force that caused the difference in acceleration is frictional force

E) To find the magnitude of the force that caused the difference in acceleration, we will use the formula;

F - F_f = ma

F_f = F - ma

Where F_f is the frictional force

Thus;

F_f = 10000 - 1267(3.51)

F_f = 5552.83 N