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3 years ago

Which of the following is not a surface feature of the Sun? a. sunspots c. prominences and flares b. corona d. CME's

Physics

2 answers:

Feliz [49]3 years ago

6 0

Answer:

The correct answer would be b. corona.

The surface feature of the sun includes solar prominences, sunspots, solar flares, and coronal mass ejections (CME's).

Corona refers to the aura of plasma that is present around the stars including sun.

The sun's corona can be seen only during a total solar eclipse when it is seen in the irregular form which appears very shiny like a pearl which surrounds the dark disk of the moon.

MArishka [77]3 years ago

4 0

I believe it would be the corona

You might be interested in

An electron moves in a circular path perpendicular to a magnetic field of magnitude 0.245 T. If the kinetic energy of the electr

Amiraneli [1.4K]

Answer

Given,

Magnetic field, B = 0.245 T

KE of the electron = 2.90 x 10⁻¹⁹ J

Speed of electron = ?

$KE = \dfrac{mv^2}{2}$

$v=\sqrt{\dfrac{2(KE)}{m}}$

$v=\sqrt{\dfrac{2\times 2.90\times 10^{-19}}{9.11\times 10^{-31}}}$

v = 7.97 x 10⁵ m/s

radius of the circular path

so,

$\dfrac{mv^2}{r}=evB$

$r=\dfrac{mv}{eB}$

$r=\dfrac{9.11\times 10^{-31}\times 7.97 \times 10^5}{1.6\times 10^{-19}\times 0.245}$

r = 1.85 x 10⁻⁵ m

8 0

3 years ago

A student pedaling a bicycle applies a net force of 400 N. The mass of the rider and the bicycle is 25 kg. What is the accelerat

Svetllana [295]

The acceleration is $16 m/s^2$

Explanation:

We can answer this question by using Newton's second law, which states that the net force acting on an object is equal to the product between the mass of the object and its acceleration:

$F=ma$

where

F is the force

m is the mass

a is the acceleration

In this problem, we have

m = 25 kg is the mass of the rider+bicycle

F = 400 N is the force

Solving for a, we find the acceleration:

$a=\frac{F}{m}=\frac{400}{25}=16 m/s^2$

Learn more about Newton's second law:

brainly.com/question/3820012

#LearnwithBrainly

6 0

4 years ago

Read 2 more answers

Two electrons exert a force of repulsion of 1.2 N on each other. How far apart are they? The elementary charge is 1.602 × 10−19

aleksandr82 [10.1K]

Answer:

The answer to your question is distance between these electrons

= 1.386 x 10⁻¹⁴ m

Explanation:

Data

Force = F = 1.2 N

distance = d = ?

charge = q₁ = q₂ = 1.602 x 10⁻¹⁹ C

K = 8.987 x 10⁹ Nm²/C²

Formula

-To solve this problem use the Coulomb's equation

F = kq₁q₂ / r²

-Solve for r²

r² = kq₁q₂ / F

-Substitution

r² = (8.987 x 10⁹)(1.602 x 10⁻¹⁹)(1.602 x 10⁻¹⁹) / 1.2

- Simplification

r² = 2.306 x 10⁻²⁸ / 1.2

r² = 1.922 x 10⁻²⁸

-Result

r = 1.386 x 10⁻¹⁴ m

7 0

4 years ago

A briefcase sits stationary in an elevator. The mass of the briefcase if 4.5 kg. The elevator then begins accelerating upwards a

Korvikt [17]

Answer:

D. 48.985 N

Explanation:

Newton's second law states that:

$\sum F = ma$

which means that the net force acting on an object is equal to the product between the object's mass and its acceleration.

The equation of the forces for the briefcase in the elevator therefore is given by:

$N-mg=ma$

where

N is the normal reaction exerted on the briefcase

(mg) is the weight of the briefcase, with

m = 4.5 kg being its mass

g = 9.8 m/s^2 is the acceleration of gravity

a = 1.10 m/s^2 is the acceleration

Here we chose upward as positive direction.

Solving for N, we find the normal force:

$N=mg+ma=m(g+a)=(4.5)(9.81+1.10)=49.095 N$

So the closest answer is

D. 48.985 N

3 0

3 years ago

A 10 kg box hangs from a rope. What is the tension in the rope (in Newtons) if the box is stationary

Archy [21]

Answer:

T = 98 N

Explanation:

The gravity of the earth is known to be 9.8 m/s²

Data:

m = 10 kg
g = 9.8 m/s²
T = ?

Use formula:

$\boxed{\bold{T=m*g}}$

Replace and solve:

$\boxed{\bold{T=10\ kg*9.8\frac{m}{s^{2}}}}$

$\boxed{\boxed{\bold{T=98\ N}}}$

The tension in the rope is <u>98 Newtons.</u>

Greetings.

5 0

3 years ago