(5 bulbs)·(60 watts/bulb)·(20 minutes)·(1 joule per sec/watt)·(60 sec/minute)
= (5·60·20·1·60) (bulb·watt·minute·joule per sec·sec) / (bulb·watt·minute)
= 360,000 joules
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Another way:
Five 60-watt bulbs = 300 watts = 0.3 kilowatt
20 minutes = 1/3 hour
(0.3 kilowatt) · (1/3 hour) = 0.1 kilowatt-hour
Answer:
a) 6.9*10^14 Hz
b) 9*10^-12 T
Explanation:
Given that
The wavelength of the wave, λ = 435 nm
Amplitude of the electric field, E(max) = 2.7*10^-3 V/m
a)
The frequency of the wave can be found by using the formula
c = fλ, where c = speed of light
f = c/λ
f = 3*10^8 / 435*10^-9
f = 6.90*10^14 Hz
b)
E(max) = B(max) * c, magnetic field amplitude, B(max) =
B(max) = E(max)/c
B(max) = 2.7*10^-3 / 3*10^8
B(max) = 9*10^-12 T
c)
1T = 1 (V.s/m^2)
Answer:
B
Explanation:
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