Answer:
0.79
Explanation:
Using Snell's law, we have that:
n(1) * sin θ1 = n(2) * sinθ2
Where n(1) = refractive index of air = 1.0003
θ1 = angle of incidence
n(2) = refractive index of second substance
θ2 = angle of refraction
The angle of reflection through the unknown substance is the same as the angle of incidence of air. This means that θ1 = 32°
=> 1.0003 * sin32 = n(2) * sin42
n(2) = (1.0003 * sin32) / sin42
n(2) = 0.79
Answer:
(a) 
(b) 
Explanation:
Given data
Solution
For Part (a)
As the velocity component in direction of y is given by:
The maximum displacement is given by:
For Part (b)
To reach y=46cm =0.46m apply:
Explanation:
Below is an attachment containing the solution.
This would be called the law of action-reaction. This states that every action will have an equal and opposite reaction. The action in the example is pulling down on the rope. The opposite and equal reaction is the climers body moving upward. The same law can be applied to a rocket. The action is the engines pushing down and the reaction is the rocket going up. :D
Answer:
The speed of the car B after the collision is same as the speed of the car A before collision.
Explanation:
lets take the mass of the car A = m kg
Initial speed of the car A = u m/s
The mass of the car B = m kg
Initial speed of the car A = 0 m/s
The final speed of the car A = 0 m/s
The final speed of the car B = v
There is no any external force on the masses that is why the linear momentum will be conserve.
Initial linear momentum = Final linear momentum
P = mass x velocity
m u + m x 0 = m x 0 + m v
m u + 0 = 0 + m v
m u = m v
v= u
Therefore we can say that ,the speed of the car B after the collision is same as the speed of the car A before collision.
