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4 years ago

What are 3 main resources from va

1 answer:

5 0

The most important mineral resources of Virginia are coal, crushed stone, sand and gravel, lime (from limestone and dolostone) and natural gas.

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What fluid surrounds the brain and spine

gulaghasi [49]

Answer:

Cerebrospinal fluid (CSF) is a clear fluid that surrounds the brain and spinal cord.

7 0

3 years ago

If u add 1.362 and 25.2 what is the correct answer?

krek1111 [17]

Answer:

26.562

Explanation:

1+25= 26

0.362+0.2= 0.562

26+0.562= 26.562

or just use a calculator

6 0

2 years ago

(TIMED) Anyone know the answer to this question?

KengaRu [80]

I believe C is your answer (also, I am also using tht same exact program!)

7 0

4 years ago

Read 2 more answers

A copper cable needs to carry a current of 160 A with a power loss of only 2.0 W/m. What is the required radius of the copper ca

lesantik [10]

Answer:

The radius of the cable is 0.0083 m or 8.3 mm.

Explanation:

The resistance of copper cable of 1 meter length will be given by

$R_{cable} = \frac{\rho \times l}{a}$ .... (i)

where the resistivity of copper is $\rho = 1.7 \times 10^{-8} \Omega.m$ , and l is the length of the wire which is considered to be 1m, and a is the cross sectional area of the wire in $m^{2}$ .

From the formula of power we know that, $P = I^2 R$ .... (ii)

Therefore 2 W/m = $(160)^2 \times R$ .... (iii)

where the resistance,R, actually means the resistance of the cable per meter.

Therefore R ( resistance of cable per meter)

= $\frac{2}{160^2} = 7.812 \times 10^{-5}$ ohms / meter. .... (iv)

Therefore from (i)

$7.812 \times 10^{-5}$ = $\frac{1.7 \times 10^{-8} \times 1}{a} = \frac{1.7 \times 10^{-8} \times 1}{\pi r^{2} }$ ..... (v)

where cross sectional area of the cable, a = $\pi r^2$ ,

where r is the radius of the cable, and length of cable,l = 1m.

Therefore r = $\sqrt{\frac{ 1.7 \times 10^{-8}}{\pi \times 7.812 \times 10^{-5} } } = 0.0083m = 8.3 mm$

5 0

3 years ago

a 1010 W radiant heater is constructed to operate at 115 V. (a) What is the current in the heater when the unit is operating?

scZoUnD [109]

Answer:

Explanation:

Given data:

power rating of the heater P= 1010 W

voltage of the heater V= 115 volts

current taken by the heater I= ?

We can apply the power formula to solve for the current in the heater

i.e P= IV

Making I the current subject of formula we have

I= P/V

Substituting our given data into the expression for I we have

I=1010/115= 8.78 A

<h2 /><h2><em>Hence the current when the unit/heater is operating is 8.78 Amp</em></h2>

5 0

3 years ago