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Stella [2.4K]
2 years ago
7

What happens when an object is moved against gravity, such as rolling a toy car up a ramp?

Physics
1 answer:
BlackZzzverrR [31]2 years ago
3 0

Answer:

it goes up until we help it to but the moment we stop support it gets affected by gravity and goes back

Explanation:

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A horizontal aquifer is overlain by 73.5 ft of water-saturated clay with a porosity of 0.4. The solid density of the clay partic
mr_godi [17]

Answer:

Explanation:

solution is in the attachment below

5 0
3 years ago
Help pls i need this right now
pantera1 [17]

Answer:

The x-component of F_{3} is 56.148 newtons.

Explanation:

From 1st and 2nd Newton's Law we know that a system is at rest when net acceleration is zero. Then, the vectorial sum of the three forces must be equal to zero. That is:

\vec F_{1} + \vec F_{2} + \vec F_{3} = \vec O (1)

Where:

\vec F_{1}, \vec F_{2}, \vec F_{3} - External forces exerted on the ring, measured in newtons.

\vec O - Vector zero, measured in newtons.

If we know that \vec F_{1} = (70.711,70.711)\,[N], \vec F_{2} = (-126.859, 46.173)\,[N], F_{3} = (F_{3,x},F_{3,y}) and \vec O = (0,0)\,[N], then we construct the following system of linear equations:

\Sigma F_{x} = 70.711\,N - 126.859\,N +F_{3,x} = 0\,N (2)

\Sigma F_{y} = 70.711\,N + 46.173\,N+F_{3,y} = 0\,N (3)

The solution of this system is:

F_{3,x} = 56.148\,N, F_{3,y} = -116.884\,N

The x-component of F_{3} is 56.148 newtons.

5 0
3 years ago
What is required foe electricity to flow
lukranit [14]
Conductivity is required for the electric current to flow.
5 0
3 years ago
The wave frequency is where 1 hertz equals 1 wave passed a fixed point in 1 second.
ahrayia [7]

                     (10 waves) / (5 sec) 

                 =  (10/5) (wave/sec)

                 =      2      per sec

                 =      2        Hz .
3 0
3 years ago
7 Consider two homogeneous bodies of
kupik [55]

Answer:

No, it is not necessary for them to have same mass.

Explanation:

Let both bodies have a density d1 and d2 respectively.

Since their volumes are equal V1 = V2

we know that,

density = \frac{mass}{volume}

Hence, d1 = \frac{m1}{V1} and d2 = \frac{m2}{V2}  

Taking the ratio of densities,we get

\frac{d1}{d2} = \frac{m1}{m2}

This implies that unless the bodies have same densities, the mass of the two bodies will not be same.

3 0
3 years ago
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