Answer:
The magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F
Explanation:
Given;
magnitude of the magnetic force is F at 14.0⁰ with respect to the field.
To determine the magnitude of the magnetic force at 32.5⁰ to the field, we apply the following formula and solve with proportion;
f*Sin(14.0⁰) = F
f*Sin(32.5⁰) = ?

Therefore, the magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F
Answer:
Explanation:
The horizontal distance traveled by the projectile is given by the formula

The formula for the time of flight is given by

Case I: when the launch angle is 30°
So, 

Horizontal velocity = u Cos 30 = 0.866 u

Case II: when the launch angle is 60°


Horizontal velocity = u Cos 60 = 0.5 u

By observing the case I and case II, we conclude that
R1 = R2
Horizontal velocity 1 > Horizontal velocity 2
T1 < T2
GPE= height x mass x gravitational field strength
5 x 10 x 9,8=490J