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svlad2 [7]
3 years ago
7

The rate at which work is done is called _____

Physics
2 answers:
Harlamova29_29 [7]3 years ago
7 0
That's the quantity called "power".
maw [93]3 years ago
5 0

Answer:

power

Explanation:

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What happens during
alukav5142 [94]

Answer:

B

Explanation:

8 0
3 years ago
Read 2 more answers
If the magnitude of the magnetic force on a proton is F when it is moving at 14.0 o with respect to the field, what is the magni
sergeinik [125]

Answer:

The magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F

Explanation:

Given;

magnitude of the magnetic force is F at 14.0⁰ with respect to the field.

To determine the magnitude of the magnetic force at 32.5⁰ to the field, we apply the following formula and solve with proportion;

f*Sin(14.0⁰) = F

f*Sin(32.5⁰) = ?

= \frac{f*Sin(32.5^o)}{f*Sin(14.0^o)}.F\\\\ =2.22 \ F

Therefore, the magnitude of the magnetic force at 32.5⁰ to the field, is 2.22 F

6 0
4 years ago
Can someone please here me I’m confused
Naddika [18.5K]
I would say z, x, y, w
5 0
4 years ago
Based on the data collected, explain why a launch angle of 30 degrees (HIGH HORIZONTAL VELOCITY & SMALL TIME OF FLIGHT) will
Gennadij [26K]

Answer:

Explanation:

The horizontal distance traveled by the projectile is given by the formula

R=\frac{u^{2}Sin2\theta }{g}

The formula for the time of flight is given by

T = \frac{2u Sin\theta }{g}

Case I: when the launch angle is 30°

So, R_{1}=\frac{u^{2}Sin60 }{g}

R_{1}=\frac{0.866u^{2}}{g}

Horizontal velocity = u Cos 30 = 0.866 u

T_{1} = \frac{2u Sin30 }{g}=\frac{u}{g}

Case II: when the launch angle is 60°

R_{2}=\frac{u^{2}Sin120}{g}

R_{2}=\frac{0.866u^{2}}{g}

Horizontal velocity = u Cos 60 = 0.5 u

T_{1} = \frac{2u Sin60 }{g}=\frac{1.73 u}{g}

By observing the case I and case II, we conclude that

R1 = R2

Horizontal velocity 1 > Horizontal velocity 2

T1 < T2

5 0
3 years ago
What is the Potential Energy of ball 1??
Dvinal [7]
GPE= height x mass x gravitational field strength 
5 x 10 x 9,8=490J
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4 years ago
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