Answer:
196.2 J
Explanation:
PE = mass x accel. due to gravity x height
= 10 kg x 9.81 m/s² x 2 m
= 196.2 J
Answer:
T= 1.71×10^{-3} sec= 1.71 mili sec
t_{fc}= 4.281×10^{-4} sec or 0.4281 mili sec
Explanation:
First of all we write equation for current oscillation in LC circuits. Note, the maximum current (I_0)= 5.5 mA is the amplitude of this function. Then, we continue to solve for the angular frequency(ω). Afterwards, we calculate the time period T. qo = maximum charge on capacitor. = 1.5× 10 ^− 6 C
a) I(t) = -ωqosin(ωt+φ)
⇒Io= ωqo
⇒ω= Io/qo
also we know that T= 2π/ω
⇒T= 
now putting the values we get
= 
= 1.71×10^{-3} sec
b) note that the time
it takes the capacitor to from uncharge to fully charged is one fourth of the period . That is


t_{fc}= 4.281×10^{-4} sec or 0.4281 mili sec
Answer:
intinal speed should be 10
Explanation:
v = v0 + at
30 = v0 +10.2
then v0= 10
Answer:
6.86 N
Explanation:
Applying,
F = mg............... Equation 1
Where F = Force exerted by gravity on the mass, m = mass, g = acceleration due to gravity
Note: The Force exerted by gravity on the mass is thesame as the weight of the body.
From the question,
Given: m = 700 g = (700/1000) = 0.7 kg
Constant: g = 9.8 m/s²
Substitute these values into equation 1
F = 9.8(0.7)
F = 6.86 N
it allows only a reduced number of electrons to flow through it.