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kati45 [8]
3 years ago
12

A student walks downstairs to class. Which statement correctly describes the types of energy the student has at the top of the s

tairs and as she walks down the
stairs?
A kinetic energy at the top of the stairs, kinetic energy as she walks down
B. potential energy at the top of the stairs, potential energy as she walks down
OC kinetic energy at the top of the stairs, potential energy as she walks down
OD potential energy at the top of the stairs, kinetic energy as she walks down
Physics
1 answer:
AveGali [126]3 years ago
8 0

Answer:

D potential energy at the top of the stairs, kinetic energy as she walks down

Explanation:

The potential energy of a body is the energy due to the position of the body.

At the top of the stair case, the student is at a significant height.

Kinetic energy is the energy due to the motion of the body.

As the student descends, the potential energy is changed to kinetic energy.

 To find the potential energy;

          P.E  = mgH

 m is the mass

 g is the acceleration due to gravity

 H is the height of the body

 To find the kinetic energy;

         K.E  = \frac{1}{2} m v²

   m is the mass

   v is the velocity

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Answer:

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Explanation:

It says “Momentum before the collision is equal to momentum after the collision.” Elastic Collision formula is applied to calculate the mass or velocity of the elastic bodies.

m_{1} v_{1}=m_{2} v_{2}

\mathrm{m}_{1} \text { and } \mathrm{m}_{2} \text { are masses of the object }

\mathrm{v}_{1} \text { velocity before the collision }

\mathrm{v}_{2} \text { velocity after the collision }

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\text { Velocity before the collision } v_{1}=5 \mathrm{m} / \mathrm{s}

600 \times 5=900 \times v_{2}

3000=900 \times v_{2}

\mathrm{v}_{2}=\frac{3000}{900}

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Explanation:

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Answer:

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