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kati45 [8]
3 years ago
12

A student walks downstairs to class. Which statement correctly describes the types of energy the student has at the top of the s

tairs and as she walks down the
stairs?
A kinetic energy at the top of the stairs, kinetic energy as she walks down
B. potential energy at the top of the stairs, potential energy as she walks down
OC kinetic energy at the top of the stairs, potential energy as she walks down
OD potential energy at the top of the stairs, kinetic energy as she walks down
Physics
1 answer:
AveGali [126]3 years ago
8 0

Answer:

D potential energy at the top of the stairs, kinetic energy as she walks down

Explanation:

The potential energy of a body is the energy due to the position of the body.

At the top of the stair case, the student is at a significant height.

Kinetic energy is the energy due to the motion of the body.

As the student descends, the potential energy is changed to kinetic energy.

 To find the potential energy;

          P.E  = mgH

 m is the mass

 g is the acceleration due to gravity

 H is the height of the body

 To find the kinetic energy;

         K.E  = \frac{1}{2} m v²

   m is the mass

   v is the velocity

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A) x=\pm \frac{A}{2\sqrt{2}}

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E=\frac{1}{2}kA^2 (1)

where k is the spring constant.

The total energy, which is conserved, at any other point of the motion is the sum of elastic potential energy and kinetic energy:

E=U+K=\frac{1}{2}kx^2+\frac{1}{2}mv^2 (2)

where x is the displacement, m the mass, and v the speed.

We want to know the displacement x at which the elastic potential energy is 1/3 of the kinetic energy:

U=\frac{1}{3}K

Using (2) we can rewrite this as

U=\frac{1}{3}(E-U)=\frac{1}{3}E-\frac{1}{3}U\\U=\frac{E}{4}

And using (1), we find

U=\frac{E}{4}=\frac{\frac{1}{2}kA^2}{4}=\frac{1}{8}kA^2

Substituting U=\frac{1}{2}kx^2 into the last equation, we find the value of x:

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In this case, the kinetic energy is 1/10 of the total energy:

K=\frac{1}{10}E

Since we have

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And so we find:

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