Question

To see if your results are reasonable, you can compare the final velocity of the stone as it falls down unwinding the wire from the pulley, to the velocity the stone would have if falling the same distance while unconnected to the pulley. What is the velocity of an untethered stone after falling 0.337 m from rest

Answer 1

Answer:

The velocity of the stone is 2.57 m/s.

Explanation:

Given that

Height = 0.337 m

We need to calculate the velocity of the stone

Using equation of motion

$v^2-u^2=2gh$

Where, v = velocity of stone

u = initial velocity

g = acceleration due to gravity

h = height

Put the value into the formula

$v^2-0=2\times9.8\times 0.337$

$v=\sqrt{2\times9.8\times0.337}$

$v=2.57\ m/s$

Hence, The velocity of the stone is 2.57 m/s.