1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Cerrena [4.2K]
3 years ago
13

A can of butane with a pressure of 2 atm at 283k has its pressure increased to a new pressure of 5 atm. What is the temperature

of the new container?
Chemistry
1 answer:
Ber [7]3 years ago
6 0

Answer:

New temperature T2 = 707.5 K (Approx.)

Explanation:

Given:

Old pressure P1 = 2 atm

Old temperature T1 = 283 K

New Pressure P2 = 5 atm

Find:

New temperature T2

Computation:

Using Gay-Lussac law;

P1 / T1 = P2 / T2

So,

2 / 283 = 5 / T2

New temperature T2 = 707.5 K (Approx.)

You might be interested in
Any element can always be identified by its:
Alborosie

Explanation:

atomic mass

Really...i think it can also be atomic number..

3 0
3 years ago
Which phase change temperatures are identical on the phase diagram? Select all that apply.
inna [77]

boiling point - condensation point

is the answer i would choose because it makes more scene

5 0
3 years ago
Read 2 more answers
When 0.491 grams of a protein were dissolved in 44 mL of benzene at 24.4 degrees C, the osmotic pressure was found to be 50.9 to
Ira Lisetskai [31]

Answer:

4057.85 g/mol

Explanation:

Hello, the numerical procedure is shown in the attached file.

- In this case, since we don't have the density of the protein, we must assume that the volume of the solution is solely given by the benzene's volume, in order to obtain the moles of the solute (protein).

-Van't Hoff factor is assumed to be one.

Best regards.

4 0
3 years ago
25.0 mL of a hydrofluoric acid solution of unknown concentration is titrated with 0.200 M NaOH. After 20.0 mL of the base soluti
lesantik [10]

Answer:

[HF]₀ = 0.125M

Explanation:

NaOH + HF => NaF + H₂O

Adding 20ml of 0.200M NaOH into 25ml of HF solution neutralizes 0.004 mole of HF leaving 0.004 mole NaF in 0.045L with 0.001M H⁺ at pH = 3.   This is 0.089M NaF and 0.001M HF remaining.

=> 45ml of solution with pH = 3 and contains 0.089M NaF from titration becomes a common ion problem.

                HF  ⇄    H⁺    +      F⁻

C(eq)       [HF]     10⁻³M      0.089M (<= soln after adding 20ml 0.200M NaOH)

Ka = [H⁺][F⁻]/[HF]₀ => [HF]₀ = [H⁺][F⁻]/Ka

[HF]₀ = (0.001)(0.089)/(7.1 x 10⁻⁴) M = 0.125M

6 0
3 years ago
Explain the term "amphoteric"
Natali5045456 [20]
A substance either an ion or a molecule that can act either an acid or a base depending on a medium is called Amphoteric. Some metals like zinc, tin, copper and aluminium which produce either metal oxides or hydroxides are examples of amphoteric. During the Amphoterism, the metal compound acts either an acid or a base depending on their oxidation state.
4 0
3 years ago
Other questions:
  • For the following scenarios what is the metal? A piece of metal weighing 59.047 g was heated to 100.0 degree C and then put it i
    10·1 answer
  • Determine the highest temperature at which reaction 2 is spontaneous
    13·1 answer
  • The student decided to do another experiment with his leftover copper(II) sulfate (CuSO4) solution. He divided the solution up i
    12·1 answer
  • What Structure keeps harmful chemicals out of the animal cells
    13·2 answers
  • For each metal complex give the coordination number for the metal species. m(nh34cl2
    5·1 answer
  • What does the R stand for in the ideal gas law (PV=nRT)?
    8·1 answer
  • What is the name of the isotope produced when Californium-251 emits an alpha particle?
    6·1 answer
  • Number of atoms presented in H2so4​
    9·2 answers
  • What is the value of 100 ºC on the Kelvin scale? A. 100 K B. 273 K C. 373 K D. -373 K E. -300 K
    11·2 answers
  • Which element has 5 energy levels and 2 valence electrons?
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!