Answer:
Hello the diagram related to your question is attached below
answer: a) 851 m/s
b) 8506.1 secs
Explanation:
calculate the periodic time of the satellite using the equation below
t =
-- ( 1 )
where ; R = 6370 km
h = 500 km
g = 9.81 m/s^2
input given values into equation 1
t = 5670.75 secs
next calculate the periodic time taken by the space craft
<u>a) determine the increase in speed </u>
V = v -
where ; v = 8463 m/s , R = 6370 km, h = 500 km
V = 851 m/s
b) Determine the periodic time for the elliptic orbit
τ = 
=
= 8506.1 secs
attached below is the remaining part of the detailed solution
Answer:
D
Explanation:
The power equation is P= V^2/R
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F = 10 N
d = 20 m
θ = 0°
W = F (dot product) D = F * D * cos(angle between them)
W = FDcosθ
W = 10 * 20 * cos0 = 200 J
That depends on what you want to use them for.
As sources of light, they are somewhere around 15% - 20% efficient.
As heaters, they are somewhere around 80% - 85% efficient.