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3 years ago

The x axis of a trajectory represents its ____________.

Physics

1 answer:

lubasha [3.4K]3 years ago

4 0

The x axis of the trajectory will show the displacement in X direction only

So it is the Horizontal range

Correct answer would be

Displacement in the horizontal direction(my guess)

The stone is projected horizontally at height 64.8 m

now we can use kinematics in Y direction

$\Delta y = v_y * t +\frac{1}{2} gt^2$

now we have

$64.8 = 0 + \frac{1}{2}*9.8*t^2$

$t = 3.64 s$

so here it will fall in the air for time t = 3.64 s

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A series circuit has a 100-Ω resistor, 4.00-mH inductor and a 0.100-μF capacitor connected across a 120-V rms ac source at the r

scZoUnD [109]

Answer:

144 watt

Explanation:

resistance, R = 100 ohm

L = 4 mH

C = 100 micro farad

At resonance, the impedance is equal to R

Z = R

Vrms = 120 V

Irms = Vrms / R = 120 / 100 = 1.2 A

Power is given by

P = Vrms x Irms x CosФ

Where, CosФ is called power factor

At resonance, CosФ = 1

Power, P = Irms x Vrms

P = 1.2 x 120 x 1

P = 144 Watt.

Thus, the power is 144 watt.

6 0

4 years ago

A baseball player hits a 140 g baseball with a force of 2800 N. What is the

Murljashka [212]

B because 2800 divide by 40 is 20

6 0

3 years ago

A 1500 kg car skids to a halt on a wet road where μk = 0.47. You may want to review (Pages 141 - 145) . Part A How fast was the

shusha [124]

The car travels at a speed of 25m/s.

Explanation:

Given-

Mass, m = 1500kg

Coefficient of friction, μk = 0.47

Distance, x = 68m

Speed, s = ?

We know,

$Force, F = ma$

and

F = μ X m X g

Therefore,

μ * m * g = m * a

μ * g = a

Let, g = 9.8m/s²

So,

$a = 0.47 * 9.8 m/s^2$

$a = 4.606m/s^2$

We know,

$v^2 - u^2 = 2as$

where, v is the final velocity

u is the initial velocity

a is the acceleration

s is the distance

If the car comes to rest, the final velocity, v becomes 0.

So,

$u^2 = 2 * 4.606 * 68\\\\u^2 = 626.416m/s\\\\u = 25m/s$

The car travels at a speed of 25m/s.

6 0

3 years ago

A 2150 kg satellite used in a cellular telephone network is in a circular orbit at a height of 780 km above the surface of the e

Tom [10]

Answer:

a) $F=16741.9N$

b) $\frac{F}{W}=0.795$

Explanation:

The gravitational force on the satellite is calculated with Newton's Gravitation Law:

$F=\frac{GMm}{r^2}$

Where $M=5.97\times10^{24}kg$ is Earth's mass, $m=2150kg$ is the satellite mass, $r=R+h$ is the distance between their centers, where $h=780000m$ is the height of the satellite (from Earth's surface) and $R=6371000m$ is Earth's radius, and $G=6.67\times10^{-11}Nm^2/kg^2$ is the gravitational constant.

a) With these values we then have:

$F=\frac{GMm}{r^2}=\frac{(6.67\times10^{-11}Nm^2/kg^2)(5.97\times10^{24}kg)(2150kg)}{(6371000m+780000m)^2}=16741.9N$

b) And the fraction this force is of the satellite’s weight W=mg is:

$\frac{F}{W}=\frac{GMm}{mgr^2}=\frac{GM}{gr^2}=\frac{(6.67\times10^{-11}Nm^2/kg^2)(5.97\times10^{24}kg)}{(9.8m/s^2)(6371000m+780000m)^2}=0.795$

5 0

4 years ago

The nucleus contains protons and neutrons. Being positively charged, the protons repel each other. The nucleus should fly apart

Arte-miy333 [17]

this is due to the existence of other forces called the strong nuclear forces that overcomes the repulsion forces between the protons and keeps the nucleons holding to each other also there is a type of energy that is called the nuclear binding energy and this energy also works on binding the components of the nucleus together

6 0

3 years ago