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3241004551 [841]
3 years ago
14

Find all the missing elements:

Physics
1 answer:
djverab [1.8K]3 years ago
4 0

Answer: 80

Explanation:

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Why did Archimedes shout eureka what did he find out?
Natalka [10]

Answer:

I believe he shouted eureka after he stepped into a bath and noticed that the water rose. He then realized that the volume of water displaced must be equal to the volume of the part of his body he had submerged

Explanation:

8 0
3 years ago
A player kicks a football from ground level with a velocity of 27.0 m/s at an angle of 30o above the horizontal.
olga_2 [115]
The horizontal distance is 23.4m/s

5 0
3 years ago
A steel ball bearing with a radius of 1.5 cm forms an image of an object that has been placed 1.1 cm away from the bearing’s sur
Nonamiya [84]

Answer:

Check the explanation

Explanation:

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

The image is virtual

The image is upright

given

R = 1.5 cm

object distance, u = 1.1 cm

focal length of the ball, f = -R/2

= -1.5/2

= -0.75 cm

let v is the image distance

use, 1/u + 1/v = 1/f

1/v = 1/f - 1/u

1/v = 1/(-0.75) - 1/(1.1)

v = -0.446 cm <<<<<---------------Answer

magnification, m = -v/u

= -(-0.446)/1.1

= 0.405 <<<<<<<<<---------------Answer

Kindly check the diagram in the attached image below.

5 0
3 years ago
Calculate the net force on particle q1.
antoniya [11.8K]

By applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.

<h3>Distance between q₂ and q₃</h3>

The distance between the second charge and the third charge is given as;

r = 0.3 m

<h3>Force on q₂ due to q₃</h3>

F_{2} = \frac{kq_2q_3}{r^2} \\\\F_{2}= \frac{(8.99\times10^9) (7.7 \times 10^{-6})(5.9\times 10^{-6}) }{0.3^2} \\\\F_2 = 4.54\ N

<h3>Net force on particle q₁</h3>

The net force on particle q₁ is determined by summing the individual forces together;

F(net) = F₁ + F₂

F(net) = -14.4 + 4.54

F(net) = -9.86 N

Thus, by applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.

Learn more about Coulomb's law here: brainly.com/question/24743340

7 0
2 years ago
Consider the example of a positive charge q moving in the negative z-direction with speed v with the local magnetic field of mag
MA_775_DIABLO [31]

Answer:

<em>F</em> = <em>0</em>

Explanation:

This problem can be solved by using the equation for the force produced by a magnetic field over a charge

<em>F</em> = q<u><em>v</em></u> X <em>B</em>

That is, the cross product between velocity and the magnetic field.

In this case, v is in the negative z-direction <em>v</em> = -v k^,

and the magnetic field is in the positive z-direction <em>B</em> = z k^

Hence, the cross product is

F = q<em>v </em>X <em>B</em> = 0i^ - 0j^ + 0k^ = <em>0</em>

In this case the net force is zero due to both velocity and magnetic field vectors are in the z-direction

4 0
3 years ago
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