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1 year ago

Calculate the net force on particle q1.

Physics

1 answer:

antoniya [11.8K]1 year ago

7 0

By applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.

<h3>Distance between q₂ and q₃</h3>

The distance between the second charge and the third charge is given as;

r = 0.3 m

<h3>Force on q₂ due to q₃</h3>

$F_{2} = \frac{kq_2q_3}{r^2} \\\\F_{2}= \frac{(8.99\times10^9) (7.7 \times 10^{-6})(5.9\times 10^{-6}) }{0.3^2} \\\\F_2 = 4.54\ N$

<h3>Net force on particle q₁</h3>

The net force on particle q₁ is determined by summing the individual forces together;

F(net) = F₁ + F₂

F(net) = -14.4 + 4.54

F(net) = -9.86 N

Thus, by applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.

Learn more about Coulomb's law here: brainly.com/question/24743340

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2. A jack exerts a vertical force of 4.5 X 103

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Correct Question:-

A jack exerts a vertical force of 4.5 × 10³

newtons to raise a car 0.25 meter. How much

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Solution:-

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$\dashrightarrow \sf work = (4.5 \times 1 {0}^{3} ) \times \frac{5}{10} \\$

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$\dashrightarrow \sf work = \dfrac{4\cancel.5}{10} \times 1 {0}^{3} \times \dfrac{1}{2} \\$

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$\dashrightarrow \sf work = \dfrac{45}{10} \times 1 {0}^{3} \times \dfrac{1}{2} \\$

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$\dashrightarrow \sf work = \dfrac{45}{10 {}^{0} } \times 1 {0}^{3 - 1} \times \dfrac{1}{2} \\$

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$\dashrightarrow \sf work = \dfrac{45}{10 {}^{0} } \times 1 {0}^{2} \times \dfrac{1}{2} \\$

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$\dashrightarrow \sf work = \dfrac{45}{1} \times 1 {0}^{2} \times \dfrac{1}{2} \\$

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$\dashrightarrow \sf work = \dfrac{45 \times 10 \times \cancel{10}}{ \cancel2} \\$

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$\dashrightarrow \sf work = \dfrac{45 \times 10 \times 5}{ 1} \\$

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$\dashrightarrow \sf work =225 \times 10$

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$\dashrightarrow \bf work =\red{2250\: joule}$

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