By applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.
<h3>Distance between q₂ and q₃</h3>The distance between the second charge and the third charge is given as;
r = 0.3 m
<h3>Force on q₂ due to q₃</h3>The net force on particle q₁ is determined by summing the individual forces together;
F(net) = F₁ + F₂
F(net) = -14.4 + 4.54
F(net) = -9.86 N
Thus, by applying Coulomb's law between the charges, the net force on the charged particle q₁ due to particle q₂ and q₃ is -9.86 N.
Learn more about Coulomb's law here: brainly.com/question/24743340
We have that The acceleration due to gravity on the Moon And
The acceleration due to gravity on the surface of the Earth is approximately
From the Question we are asked
The value of G on earth and moon?
Where G refers to The acceleration due to gravity
Generally
The acceleration due to gravity on the Moon is approximately
And
The acceleration due to gravity on the surface of the Moon is approximately
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initial speed of the stuntman is given as
angle of inclination is given as
now the components of the velocity is given as
here it is given that the ramp on the far side of the canyon is 25 m lower than the ramp from which she will leave.
So the displacement in vertical direction is given as
by solving above equation we have
Now in the above interval of time the horizontal distance moved by it is given by
since the canyon width is 77 m which is less than the horizontal distance covered by the stuntman so here we can say that stuntman will cross the canyon.