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3 years ago

It’s My Final Test I’m not sure what the answer is

Mathematics

2 answers:

cestrela7 [59]3 years ago

7 0

Answer:

The answer is B .

Step-by-step explanation

Firstly

= (8 - √2 ) × ( 9 + √5 ) (writing the given only )

= 8 ( 9 + √5) - √2 ( 9+√5 ) ( multiplying them )

= 72 + 8√5 - 9√2 - √10

Hope you got it now

Elena-2011 [213]3 years ago

4 0

Answer:

Step-by-step explanation:

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Helppppppppppppppppppppppp please

baherus [9]

Answer:

Step-by-step explanation:

Two Squares

There are 2 squares at the top and bottom. All sides = 3

2* s^2

2 * 3^2

2 * 9

Middle Figure.

Triangles

There are many ways to solve this. I think the most easily understood is to break it into 2 triangles and a rectangle.

Base of both triangles = 5 + 5 = 10

The height of each triangle = (7 - 3)/2 = 4/2 = 2. You divide by 2 because there are 2 bases -- one in each triangle.

Area = 1/2 * 2 * 10 = 10

But there are 2 of them so the total area is 20

Rectangle

The length of the rectangle = 5 + 5 = 10

The width = 3

Area = 30

Total

Total Area = 2 squares + 2 triangles + 1 rectangle

Total Area = 18 + 20 + 30 = 68

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3 years ago

Susan makes $22 per hour in a clerical position. If she works 30 hours per week, what is her gross

Rzqust [24]

Select D $660 is the answer

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3 years ago

Wich type of statement has the form "if a,then b?

adell [148]

A conditional sentence

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3 years ago

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What is the mean? If the answer is a decimal, round it to the nearest tenth.

Rasek [7]

Answer:

Round out to the nearest 10th say 5 it would stay 5 unlike 8 would round to 10

Step-by-step explanation:

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3 years ago

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The graph of f(x) = x^2 has been shifted into the form f(x) = (x − h)^2 + k

stepan [7]

$\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
y=&{{ A}}({{ B}}x+{{ C}})+{{ D}}
\\ \quad \\
f(x)=&{{ A}}\sqrt{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}}(\mathbb{R})^{{{ B}}x+{{ C}}}+{{ D}}
\\ \quad \\
f(x)=&{{ A}} sin\left({{ B }}x+{{ C}} \right)+{{ D}}
\end{array}\\\\
--------------------\\\\$

$\bf \bullet \textit{ stretches or shrinks horizontally by } {{ A}}\cdot {{ B}}\\\\
\bullet \textit{ flips it upside-down if }{{ A}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the x-axis}
\\\\
\bullet \textit{ flips it sideways if }{{ B}}\textit{ is negative}\\
\left. \qquad \right. \textit{reflection over the y-axis}$

$\bf \bullet \textit{ horizontal shift by }\frac{{{ C}}}{{{ B}}}\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is negative, to the right}\\\\
\left. \qquad \right. if\ \frac{{{ C}}}{{{ B}}}\textit{ is positive, to the left}\\\\
\bullet \textit{ vertical shift by }{{ D}}\\
\left. \qquad \right. if\ {{ D}}\textit{ is negative, downwards}\\\\
\left. \qquad \right. if\ {{ D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{ B}}}$

with that template in mind, let's see, it went to the right 2 units, and then up 3 units.

that simply means, C = -2, D = 3.

8 0

3 years ago