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Free_Kalibri [48]
3 years ago
10

It’s My Final Test I’m not sure what the answer is

Mathematics
2 answers:
cestrela7 [59]3 years ago
7 0

Answer:

The answer is B .

Step-by-step explanation

Firstly

   =  (8 - √2 )  × ( 9 + √5 )     (writing the given only )

   =  8 ( 9 + √5)   - √2 ( 9+√5 ) ( multiplying them )

    =  72  +  8√5  - 9√2 -  √10

 Hope you got it now

Elena-2011 [213]3 years ago
4 0

Answer:

D

Step-by-step explanation:

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Help me pls i need to answer fast
KATRIN_1 [288]

Answer:

your answer will be 1

Step-by-step explanation:

8 0
3 years ago
Pls help me with this
Vladimir79 [104]
The answer is d yes
3 0
3 years ago
Which is the following fraction is the smallest?9/13 ,17/26, 28/39, 33/52​
babunello [35]

Answer:

<h3>I THINK ITS A. 9/13 BECAUSE THE QUESTION SAID THAT FRACTION IS THE SMALLEST</h3>

Step-by-step explanation:

I HOPE IT HELPS :)

4 0
3 years ago
How many positive integers can be expressed ad a product of two or more of the prime numbers 5,7,11,and 13 if no one product is
sertanlavr [38]

Answer:

11 positive integers can be expressed.

Step-by-step explanation:

Consider the provided information.

The number of possible prime numbers are 5,7,11,and 13.

There are 4 possible prime numbers.

How many positive integers can be expressed as a product of two or more of the prime numbers, that means there can be product of two numbers, three number or four numbers.

The formula to calculate combinations is: ^nC_r=\frac{n!}{r!(n-r)!}

The number of ways are:

^4C_2+^4C_3+^4C_4=\frac{4!}{2!(4-2)!}+\frac{4!}{3!(4-3)!}+\frac{4!}{4!}

^4C_2+^4C_3+^4C_4=\frac{4!}{2!2!}+\frac{4!}{3!}+1

^4C_2+^4C_3+^4C_4=6+4+1

^4C_2+^4C_3+^4C_4=11

Hence, 11 positive integers can be expressed.

8 0
3 years ago
How to find area of sector with radius and central angle?
ddd [48]
If you have not already, convert the angle into a radius. xπ/180 where x is the angle in degrees. 

The formula for area is A=r²Ф/2 where r is radius and Ф is angle in radians. 

Solve to find the area. 

Hope I helped :) 
8 0
3 years ago
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