CI2 + 2Nal ---> 2NalCI + I2
Nal = 149.9 g/mol.
NaCI = 58.5 g/mol
2 mol Nal makes 2 mol NaCI
0.29 g Nal x ( 1 mol / 149.9 g) = 0.0019 mol NaCI
00.19 mol NaCI x ( 58.5 g / 1 mol ) 0.11 g NaCI ( 2 sig figs)
Answer:
a
b
Explanation:
From the question we are told that
The pressure of compressed gas is 
The temperature is 
Generally the perfect gas equation is mathematically represented as
substituting 0.08206 L-atm/mol-K for R and 1 mole for n
We have that
Generally the van der Waals equation is mathematically represented as
![nRT = [P + \frac{n^2 * a }{V^2 } ][V - nb]](https://tex.z-dn.net/?f=nRT%20%20%3D%20%20%5BP%20%2B%20%5Cfrac%7Bn%5E2%20%2A%20a%20%7D%7BV%5E2%20%7D%20%5D%5BV%20-%20nb%5D)
=>![1 * 0.08206 *298 = [197.4 + \frac{1^2 * 1.364}{V^2 } ][V - 1 * 3.19 * 10^{-2}]](https://tex.z-dn.net/?f=1%20%2A%20%200.08206%20%2A298%20%20%3D%20%20%5B197.4%20%2B%20%5Cfrac%7B1%5E2%20%2A%20%201.364%7D%7BV%5E2%20%7D%20%5D%5BV%20-%201%20%2A%203.19%20%2A%2010%5E%7B-2%7D%5D)
=>
Answer:
Three ways that carbon is released back to the atmosphere are burning fossil fuels, land and ocean photosynthesis and respiration and volcanoes.
Hope this helps!
Ksp=3.45×10⁻¹¹
CaF₂(s) ⇄ Ca²⁺(aq) + 2F⁻(aq)
Ksp=[Ca²⁺][F⁻]²
[Ca²⁺]=C(CaF₂)
[F⁻]=2C(CaF₂)
Ksp=4{C(CaF₂)}³
C(CaF₂)=∛(Ksp/4)
C(CaF₂)=∛(3.45×10⁻¹¹/4)=2.05×10⁻⁴ mol/L
2.05×10⁻⁴ M
Answer:
.371 mole of NaCl
Explanation:
Na Cl Mole weight = 22.989 + 35.45 = 58.439 g/mole
21.7 g / 58.439 g/mole = .371 mole
