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tester [92]
2 years ago
14

What is the chemical formula for Mg2+ and I1- ( magnesium and iodine)

Chemistry
2 answers:
NeTakaya2 years ago
8 0

Answer:MgI2

Explanation:

DENIUS [597]2 years ago
7 0
Explanation:
M
g
2
+
+
2
I
−
→
M
g
I
2
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Consider an experimental setup with two compartments separated by a phospholipid bilayer membrane containing ion channels select
Schach [20]

This question is incomplete, the complete question is;

Consider an experimental setup with two compartments separated by a phospholipid bilayer membrane containing ion channels selectively permeable only to chloride ions. The left compartment (also called inside) contains 1 mM Cl- and the right compartment (also called outside) contains 100 mM Cl-. What will the electrical potential be when the system attains equilibrium? [ assume body temperature; log 100 = 2, log 10 = 1, log 1 = 0, log 0.1 = -1, log 0.01 = -2]

Options;

a) -62 mV

b) -124 mV

c) +62 mV

d) 0 mV

e) +124 mV

Answer:

the electrical potential be when the system attains equilibrium is  –124mV

Option b) –124mV is the correct answer

Explanation:

Given the data in the question;

Two compartments are divided by lipid bilayer;

In inside compartment Cl- ion concentration- 1mM and out side of the cell concentration is 100mM

now we apply the Nernst equilibrium potential equation;

Chlorine ion valency is z = –1

So

E_{eq} = 62/z × log(ion outside/ ion inside) [for Cl‐ ions]

E_{eq} = (62 / –1) x log(  100 / 1 )

 E_{eq} = -62 x 2 =

E_{eq}  = –124mV

Therefore, the electrical potential be when the system attains equilibrium is  –124mV

Option b) –124mV is the correct answer

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True or false certain cations are associated with either exotermic or endothermic processes
erastova [34]

Explanation:

i think it is exothermic processes

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In what sequence do electrons fill the atomic orbitals within a sub level
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Each orbital must contain a single electron before any orbital contains two electrons.

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Gold is currently trading at very high price. Suppose that gold is selling for around $1860/ounce. How
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Answer:

The answer is "3.81041978"

Explanation:

\to 1 \ OZ= 28.349523125 \ grams\\\\

              =28.349523125\times {1000} \ miligrams\\\\= 28349. 5231  \ miligrams\\

In 1860 = 28349.5231 \ miligrams\\

\to In \$ \ 1 = \frac{28349.5231}{1860} \ \ miligrams\\

             = 15.2416791 \ miligrams

\ In \  1 \ quarter =  \$ \ 0.25

\to \$ \ 0.25 =  15.2416791  \times 0.25 \  miligrams\\

              = 3.81041978

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