1 2 3 4 5 6 7 8 9 10 11 12 13 14
From 1-6.5 ph acidic
From 7-14 ph alkaline
The electrophilic bromination or chlorination of benzene requires Lewis acid along with the halogen.
<h3>
What is bromination of benzene?</h3>
The bromination or chlorination of benzene is an example of an electrophilic aromatic substitution reaction.
During the reaction, the bromine forms a sigma bond to the benzene ring, yielding an intermediate. Subsequently a a proton is removed from the intermediate to form a substituted benzene ring.
This reaction is achieved with the help of Lewis acid as catalysts.
Thus, the electrophilic bromination or chlorination of benzene requires Lewis acid along with the halogen.
Learn more about bromination of benzene here: brainly.com/question/26428023
Given :
Number of moles , n = 36.25 mol .
Molarity , M = 1.25 M .
To Find :
The volume of water required .
Solution :
Moarity is given by :
![M=\dfrac{n}{V}](https://tex.z-dn.net/?f=M%3D%5Cdfrac%7Bn%7D%7BV%7D)
So , ![V=\dfrac{n}{M}](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7Bn%7D%7BM%7D)
Here , n is number of moles and M is molarity .
Putting all values in above equation , we get :
![V=\dfrac{36.25}{1.25}\\\\V=29\ L](https://tex.z-dn.net/?f=V%3D%5Cdfrac%7B36.25%7D%7B1.25%7D%5C%5C%5C%5CV%3D29%5C%20L)
Therefore , volume of water required is 29 L .
Answer: seas
Explanation:
The ancient astronomers thought the mares on the moon were seas.
H3PO4 has molecular weight of approximately 98 grams per
mole. 4.50 M is equal to 4.50 mole per 1000 mL solution of H3PO4. 255 mL times
4.50 mol /1000 mL times 98 g/mol is equal to 112.455 grams. Note that I
automatically equate 1 Liter to 1000 mL since the given volume is in mL for
easier computation.