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KIM [24]
3 years ago
7

On top a coiled spring labeled Wave A with coils, which are widely spaced then tightly spaced then widely space. On bottom a coi

led spring labeled Wave B with coils, which are widely spaced then very tightly spaced then widely space.
Which statement can be made about waves A and B?

Wave A has a lower amplitude than Wave B.
Wave A has a higher amplitude than Wave B.
Wave A has a lower frequency than Wave B.
Wave A has a higher frequency than Wave B.

Physics
2 answers:
PilotLPTM [1.2K]3 years ago
6 0

Wave A has a lower frequency than Wave B.

Explanation:

Frequency is the number of waves passing through the unit time.

As the statement of the question says that the coils in wave A are widely and tightly spaced.

While in wave B the coils are widely and very tightly spaced which means the number of coils is more and the frequency of wave B is more than wave A.

Therefore more coils will pass through a fixed point in unite time and more will be the frequency.  

soldier1979 [14.2K]3 years ago
5 0

Answer:

c

Explanation:

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Explanation:

the quantity of motion of a moving body, measured as a product of its mass and velocity.

4 0
3 years ago
What stands for sound navigation and ranging
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Sonar, originally an <span>acronym for SOund Navigation And Ranging
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6 0
4 years ago
Astronaut Rob leaves Earth in a spaceship at a speed of 0.960c relative to an observer on Earth. Rob's destination is a star sys
xxMikexx [17]

Answer:

A) 15.0 years

Explanation:

Due to the distance to the star system is in light-year units, we can compute the time by using:

t=\frac{d}{v}=\frac{14.4 l-y}{0.960}=15l-y

then, Rob will take to complete the trip about 15 light-years.

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3 0
3 years ago
An infinite long straight wire is uniformly charged, the charge density is a. Use Coulomb's law to calculate the electric field
bixtya [17]

Answer:

\vec{E} = \frac{a}{2\pi \epsilon_0 R}\^R

Explanation:

Since the wire is infinitely long, we will use Gauss' Law:

\int\vec{E}d\vec{a} = \frac{Q_{enc}}{\epsilon_0}

We will draw an imaginary cylindrical surface with height h around the wire. The electric flux through the imaginary surface will be equal to the net charge inside the surface.

In that case, the net charge inside the imaginary surface will be the portion of wire with height h. Then the charge of that portion will be equal to

Q_{enc} = ah

The left-hand side of the Gauss' Law is the flux through the imaginary surface. Since we choose our surface as a cylinder, of which we know the area, we do not have to take the surface integral.

\int\vec{E}d\vec{a} = E2\pi R h

where R is the radius of the imaginary cylinder.

Finally, Gauss' Law gives

E2\pi Rh = \frac{ah}{\epsilon_0}\\E = \frac{a}{2\pi \epsilon_0 R}

The vector expression is

\vec{E} = \frac{a}{2\pi \epsilon_0 R}\^R

As you can see, the electric field is independent from the height h, since that is merely an imaginary cylinder to apply Gauss' Law. In the end, what matters is the charge density of the wire and the distance from the wire.

4 0
4 years ago
A motorcycle of 170 kg is moving with a velocity 25m/ . Calculate the kinetic energy
topjm [15]

Answer: 53125joules

Explanation: The formula for kinetic energy is 1/2mv^2.

So we would have

1/2[(170)(25x25)]=53125

3 0
3 years ago
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