The tension in the cable is equal to 323.5 N.
<h3>What is the tension in the cable?</h3>
The tension, T in the cable is determined by taking moments about the pivot marked X.
The angles of the boom and the cable with the horizontal are first calculated.
Angle of the boom with horizontal, θ = tan⁻¹(5/10) = 26.56°
The angle of cable with horizontal, B = tan⁻¹(4/10) = 21.80
Taking moments about the pivot:
175.5 * cos 26.56 + 94.7 * cos 26.56 * 0.5 = T (sin(26.56 + 21.80) * 1
Tension = 241.68/0.747
Tension = 323.5 N
In conclusion, the tension in the cable helps to suspend the crate.
Learn more about tension at: brainly.com/question/24994188
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Answer:
energy : the ability to cause change
work : is force x distance or when an object moves a distance due to a specific force (measured in units of newtons-meters)
potential energy : is stored energy
kinetic energy : is energy in motion
mechanicle energy : the energy of motion such as a moving vechile
thermal energy : total kinetic energy in moving partsticles, like in boiling water (energy of heat)
chemical : energy stored in chemical bonds, like in plants
electromagnetic : waves with electric and magnetic properties , such as light
nuclear energy : energy stored in the nuclear atoms
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This is false. The reaction force can be determined.
Answer:
Part a)

Part b)

Part c)

Part d)

Part e)

Explanation:
Time period of Earth about Sun is 1 Year
so it is

now we know that angular speed of the Earth about Sun is given as


now speed of center of Earth is given as




Part b)
now transnational kinetic energy of center of Earth is given as



Part c)
Angular speed of Earth about its own axis is given as



Part d)
Now moment of inertia of Earth about its own axis



now rotational energy is given as



Part e)
Now total kinetic energy is given as



Answer : The atomic weight of the element is, 121.75 amu
Explanation :
Average atomic mass of an element is defined as the sum of masses of each isotope each multiplied by their natural fractional abundance.
Formula used to calculate average atomic mass follows:

As we are given that,
Mass of isotope 1 = 120.9038 amu
Percentage abundance of isotope 1 = 57.25 %
Fractional abundance of isotope 1 = 0.5725
Mass of isotope 2 = 122.8831 amu
Percentage abundance of isotope 2 = 100 - 57.25 = 42.75 %
Fractional abundance of isotope 2 = 0.4275
Now put all the given values in above formula, we get:
![\text{Average atomic mass of element}=\sum[(120.9038\times 0.5725)+(122.8831\times 0.4275)]](https://tex.z-dn.net/?f=%5Ctext%7BAverage%20atomic%20mass%20of%20element%7D%3D%5Csum%5B%28120.9038%5Ctimes%200.5725%29%2B%28122.8831%5Ctimes%200.4275%29%5D)

Therefore, the atomic weight of the element is, 121.75 amu