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levacccp [35]
3 years ago
12

What is storage tank stratification?

Engineering
1 answer:
Artist 52 [7]3 years ago
5 0

Answer:

Stratification is the process of arranging the different elements classification in a specific manner.

In the storage tank, hot water and cold water create a specific layer and coexist between them for the process of stratification. Thermal storage and heat storage exchanger are the types of storage tank, in which the stratification process take place.

The density of the cold water is more as compared to hot water. Then, due to this the cold water sink to the bottom and hot ware rises up in the storage vessel. In this way, the water gets heated and the stratification process take place in the tank.

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What are the success factors for mechanical engineering?
Eva8 [605]

Answer:

-effective technical skills.

-the ability to work under pressure.

-problem-solving skills.

-creativity.

-interpersonal skills.

-verbal and written communication skills.

-commercial awareness.

-teamworking skills.

Explanation:

is this what ur looking for? if so there ya go lol

7 0
2 years ago
Read 2 more answers
If you are interested only in the temperature range of 20° to 40°C and the ADC has a 0 to 3V input range, design a signal condit
mario62 [17]

Explanation:

Temperature range → 0 to 80'c

respective voltage output → 0.2v to 0.5v

required temperature range 20'c to 40'c

Where T = 20'c respective voltage

\begin{aligned}v_{20} &=0.2+\frac{0.5-0.8}{80} \times 20 \\&=0.2+\frac{0.3}{80} \times 20 \\V_{20} &=0.275 v\end{aligned}

\begin{aligned}\text { when } T=40^{\circ} C & \text { . } \\v_{40} &=0.2+\frac{0.5-0.2}{80} \times 40 \\&=0.35 V\end{aligned}

Therefore, Sensor output changes from 0.275v to 0.35volts for the ADC the required i/p should cover the dynamic range of ADC (ie - 0v to 3v)

so we have to design a circuit which transfers input voltage 0.275volts - 0.35v to 0 - 3v

Therefore, the formula for the circuit will be

\begin{array}{l}v_{0}=\left(v_{i n}-0.275\right) G \\\sigma=\ldots \frac{3-0}{0.35-0.275}=3 / 0.075=40 \\v_{0}=\left(v_{i n}-0.275\right) 40\end{array}

The simplest circuit will be a op-amp

NOTE: Refer the figure attached

Vs is sensor output

Vr is the reference volt, Vr = 0.275v

\begin{aligned}v_{0}=& v_{s}-v_{v}\left(1+\frac{R_{2}}{R_{1}}\right) \\\Rightarrow & \frac{1+\frac{R_{2}}{R_{1}}}{2}=40 \\& \frac{R_{2}}{R_{1}}=39 \quad \Rightarrow\end{aligned}

choose R2, R1 such that it will maintain required  ratio

The output Vo can be connected to voltage buffer if you required better isolation.

3 0
2 years ago
Easy POINTS computer genius help me plz
Norma-Jean [14]

Answer:

dedededededede

Explanation:

4 0
3 years ago
Time management is a learned behavior.<br> True<br> False
larisa [96]

Answer:

true

Explanation:

3 0
2 years ago
Read 2 more answers
A water tank filled with solar-heated water at 40°C is to be used for showers in a field using gravity-driven flow.
Alenkasestr [34]

Answer:

yes sir

Explanation:

4 0
2 years ago
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