How to cycle a cycle

Why doesn't any one give as many points as i do for random questions on brainly

erastova [34]

good question i like to give about 20. i think people just are cheapskates for most of their time on this planet. didnt need the 50 though but thanks.

4 0

2 years ago

Read 2 more answers

Methane and oxygen react in the presence of a catalyst to form formaldehyde. In a parallel reaction, methane is oxidized to carb

Nezavi [6.7K]

Answer:

$y_{CH_4}^2=\frac{5mol/s}{100mol/s}=0.05\\y_{O_2}^2=\frac{3mol/s}{100mol/s}=0.03\\y_{H_2O}^2=\frac{47mol/s}{100mol/s}=0.47\\y_{HCHO}^2=\frac{43mol/s}{100mol/s}=0.43\\y_{CO_2}^2=\frac{2mol/s}{100mol/s}=0.02$

Explanation:

Hello,

a. On the attached document, you can see a brief scheme of the process. Thus, to know the degrees of freedom, we state the following unknowns:

- $\xi_1$ and $\xi_2$ : extent of the reactions (2).

- $F_{O_2}^2$ , $F_{CH_4}^2$ , $F_{H_2O}^2$ , $F_{HCHO}^2$ and $F_{CO_2}^2$ : Molar flows at the second stream (5).

On the other hand, we've got the following equations:

- $F_{O_2}^2=50mol/s-\xi_1-2\xi_2$ : oxygen mole balance.

- $F_{CH_4}^2=50mol/s-\xi_1-\xi_2$ : methane mole balance.

- $F_{H_2O}^2=\xi_1+2\xi_2$ : water mole balance.

- $F_{HCHO}^2=\xi_1$ : formaldehyde mole balance.

- $F_{CO_2}^2=\xi_2$ : carbon dioxide mole balance.

Thus, the degrees of freedom are:

$DF=7unknowns-5equations=2$

It means that we need two additional equations or data to solve the problem.

b. Here, the two missing data are given. For the fractional conversion of methane, we define:

$0.900=\frac{\xi_1+\xi_2}{50mol/s}$

And for the fractional yield of formaldehyde we can set it in terms of methane as the reagents are equimolar:

$0.860=\frac{F_{HCHO}^2}{50mol/s}$

In such a way, one realizes that the output formaldehyde's molar flow is:

$F_{HCHO}^2=0.860*50mol/s=43mol/s$

Which is equal to the first reaction extent $\xi_1$ , therefore, one computes the second one from the fractional conversion of methane as:

$\xi_2=0.900*50mol/s-\xi_1\\\xi_2=0.900*50mol/s-43mol/s\\\xi_2=2mol/s$

Now, one computes the rest of the output flows via:

- $F_{O_2}^2=50mol/s-43mol/s-2*2mol/s=3mol/s$

- $F_{CH_4}^2=50mol/s-43mol/s-2mol/s=5mol/s$

- $F_{H_2O}^2=43mol/s+2*2mol/s=47mol/s$

- $F_{HCHO}^2=43mol/s$

- $F_{CO_2}^2=2mol/s$

The total output molar flow is:

$F_{O_2}+F_{CH_4}+F_{H_2O}+F_{HCHO}+F_{CO_2}=100mol/s$

Therefore the output stream composition turns out into:

$y_{CH_4}^2=\frac{5mol/s}{100mol/s}=0.05\\y_{O_2}^2=\frac{3mol/s}{100mol/s}=0.03\\y_{H_2O}^2=\frac{47mol/s}{100mol/s}=0.47\\y_{HCHO}^2=\frac{43mol/s}{100mol/s}=0.43\\y_{CO_2}^2=\frac{2mol/s}{100mol/s}=0.02$

Best regards.

7 0

3 years ago

8.19 - Airline Reservations System (Project Name: Airline) - A small airline has just purchased a computer for its new automated

e-lub [12.9K]

Answer:

The App is written in C++ language using dev C++.

Explanation:

/******************************************************************************

You can run this program in any C++ compiler like dev C++ or any online C++ compiler

*******************************************************************************/

#include <iostream>

using namespace std;

class bookingSeat// class for airline reservation system

{

private:

bool reserveSeat[10];// 10 seats (1-5) for first class and 6-10 for economy class

int firstClassCounter=0;//count first class seat

int economyClassCounter=5;//count economy class seat

char seatPlacement;/* switch between economy and first clas seat----- a variable for making decision based on user input*/

public:

void setFirstClassSeat()//

{

if(firstClassCounter<5)// first class seat should be in range of 1 to 5

{

reserveSeat[firstClassCounter]=1; /*set first class seat..... change index value to 1 meaning that it now it is reserved*/

cout<<"Your First Class seat is booked and your seat no is "<<firstClassCounter+1; //display seat number reserved

firstClassCounter++; //increament counter

}

else//in case seats are ful

{

cout<<"\nSeats are full";

if(economyClassCounter==10 && firstClassCounter==5)

{

cout<<"\n Next flight leaves in 3 hours.";

}

else

{

cout<<"\nIt’s acceptable to be placed to you in the first-class section y/n ";//take input from user

cin>>seatPlacement;//user input

if(seatPlacement=='y')//if customer want to reserve seat in first class

{

setEconomyClassSeat();// then reserve first class seat

}

else

{

cout<<"\n Next flight leaves in 3 hours.";

}

void setEconomyClassSeat()//set economy class seat

{

if(economyClassCounter<10)//seat ranges between 6 and 10

{

reserveSeat[economyClassCounter]=1;// reserve economy class seat

cout<<"Your Economy class seat is booked and your seat no is "<<economyClassCounter+1;//display reservation message about seat

economyClassCounter++;//increament counter

}

else// if economy class seats are fulled

{

cout<<"\nSeats are full";

if(economyClassCounter==10 && firstClassCounter==5)//check if all seats are booked in both classes

{

cout<<"\n Next flight leaves in 3 hours.";

}

else

{

cout<<"\nIt’s acceptable to be placed to you in the first-class section y/n ";//take input from user

cin>>seatPlacement;//user input

if(seatPlacement=='y')//if customer want to reserve seat in first class

{

setFirstClassSeat();// then reserve first class seat

}

else

{

cout<<"\n Next flight leaves in 3 hours.";

}

};

int main()

{ int checkseat=10;// check seat

int classType;//class type economy or first class

bookingSeat bookseat;//object declaration of class bookingSeat

while(checkseat<=10)//run the application until seats are fulled in both classes

{

cout<<"\nEnter 1 for First Class and 2 for Economy Class ";

cin>>classType;//what user entered

switch (classType)//decide which seat class to be reserved

{

case 1://if user enter 1 then reserve first class seat

bookseat.setFirstClassSeat();

break;

case 2://if user enter 2 then reserve the economy class seat

bookseat.setEconomyClassSeat();

}

return 0;

}

8 0

3 years ago

A lake has a carrying capacity of 10,000 fish. At the current level of fishing, 2,000 fish per year are taken with the catch uni

arlik [135]

Answer:

The population size would be $p' = 5000$

The yield would be $MaxYield = 2082 \ fishes \ per \ year$

Explanation:

So in this problem we are going to be examining the application of a population dynamics a fishing pond and stock fishing and objective would be to obtain the maximum sustainable yield and and the population of the fish at the obtained maximum sustainable yield, so basically we would be applying an engineering solution to fishing

So the current yield which is mathematically represented as

$\frac{dN}{dt} = \frac{2000}{1 \ year }$

Where dN is the change in the number of fish

and dt is the change in time

So in order to obtain the solution we need to obtain the rate of growth

For this we would be making use of the growth rate equation which is

$r = \frac{[\frac{dN}{dt}] }{N[1-\frac{N}{K} ]}$

Where N is the population of the fish which is given as 4,000 fishes

and K is the carrying capacity which is given as 10,000 fishes

r is the growth rate

Substituting these values into the equation

$r = \frac{[\frac{2000}{year}] }{4000[1-\frac{4000}{10,000} ]} =0.833$

The maximum sustainable yield would be dependent on the growth rate an the carrying capacity and this mathematically represented as

$Max Yield = \frac{rK}{4} = \frac{(10,000)(0.833)}{4} = 2082 \ fishes \ per \ year$

So since the maximum sustainable yield is 2082 then the the population need to be higher than 4,000 so in order to ensure a that this maximum yield the population size denoted by $p'$ would be

$p' = \frac{K}{2} = \frac{10,000}{2} = 5000\ fishes$

7 0

4 years ago

Read 2 more answers

Which is the better measure of computer system performance—a benchmark, such as SPECINT; or a processor speed measure, such as G

Vesna [10]

Answer:

A benchmark

Explanation:

Most times a benchmark serves as the better measure when assessing a computer's performance, this is because CPU speeds can only evaluate an aspect of a computer's performance whereas a benchmark offers the advantage of measuring all the aspects of a computer's performance for a specific type of computing problem.

5 0

3 years ago

How to cycle a cycle​

How to cycle a cycle