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julia-pushkina [17]
2 years ago
13

Explain how the ideal vapour compression refrigerator cycle is an improvement upon the Carnot cycle. Use any two of the problems

to explain.
Engineering
1 answer:
Grace [21]2 years ago
8 0
  • answer explanation:
  • <u>Basically, the Carnot cycle is turning a heat differential into mechanical energy, then using mechanical energy to recreate the heat differential. A heat pump only turns mechanical energy into a heat differential. It exchanges the gas being compressed on an ongoing basis and does not extract mechanical energy from it, this continuous loss of mechanical energy input is what allows continuous generation of a heat differential.</u>

  • <u>Also, the Carnot cycle is an idealized theoretical model, not a practically achievable engineering goal. It illustrates the essential mechanism by which heat differentials can be turned into mechanical energy and vice versa, it has to ignore the fact of inefficiency in conversion between mechanical energy and heat differential for the sake of illustrating a set of ideal processes. A real refrigeration system has to deal with the question of whether the system is pumping away more heat than it generates itself through inefficiency.</u>
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Which of the following is a possible consequence of poor measurement in construction as stated in the segment?
Kamila [148]

Answer:

Decreased risk of structure failure

6 0
2 years ago
In a much smaller model of the Gizmo apparatus, a 5 kg mass drops 86 mm (0.086 m) and raises the temperature of 1 gram of water
Orlov [11]

Answer:

The amount of energy transferred to the water is 4.214 J

Explanation:

The given parameters are;

The mass of the object that drops = 5 kg

The height from which it drops = 86 mm (0.086 m)

The potential energy P.E. is given by the following formula

P.E = m·g·h

Where;

m = The mass of the object = 5 kg

g = The acceleration de to gravity = 9.8 m/s²

h = The height from which the object is dropped = 0.086 m

Therefore;

P.E. = 5 kg × 9.8 m/s² × 0.086 m = 4.214 J

Given that the potential energy is converted into heat energy, that raises the 1 g of water by 1°C, we have;

The amount of energy transferred to the water = The potential energy, P.E. = 4.214 J.

6 0
2 years ago
Uestion 10
Dimas [21]
Tryna boost my score for college stuff could you give me the brainiest and a thanks? Hope you find your answer your looking for!
6 0
3 years ago
A pipe of 0.3 m outer diameter at a temperature of 160°C is insulated with a material having a thermal conductivity of k = 0.055
Alekssandra [29.7K]

Answer:

Q=0.95 W/m

Explanation:

Given that

Outer diameter = 0.3 m

Thermal conductivity of material

K= 0.055(1+2.8\times 10^{-3}T)\frac{W}{mK}

So the mean conductivity

K_m=0.055\left ( 1+2.8\times 10^{-3}T_m \right )

T_m=\dfrac{160+273+40+273}{2}

T_m=373 K

K_m=0.055\left ( 1+2.8\times 10^{-3}\times 373 \right )

K_m=0.112 \frac{W}{mK}

So heat conduction through cylinder

Q=kA\dfrac{\Delta T}{L}

Q=0.112\times \pi \times 0.15^2\times 120

Q=0.95 W/m

4 0
3 years ago
The modulus of elasticity for a ceramic material having 6.0 vol% porosity is 303 GPa. (a) Calculate the modulus of elasticity (i
Phantasy [73]

Answer:

modulus of elasticity for the nonporous material is 340.74 GPa

Explanation:

given data

porosity = 303 GPa

modulus of elasticity = 6.0

solution

we get here  modulus of elasticity for the nonporous material Eo that is

E = Eo (1 - 1.9P + 0.9P²)    ...............1

put here value and we get Eo

303 = Eo ( 1 - 1.9(0.06) + 0.9(0.06)² )  

solve it we get

Eo = 340.74 GPa

8 0
2 years ago
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