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morpeh [17]
3 years ago
9

The specifications of an electronic device are 24 /- 0.4 Amps. When the device exceeds specifications the average quality cost i

s $32.00. A sample of the devices had an average value of 23.9 Amps and a standard deviation of 0.211 Amps. What is the average loss for this device
Engineering
1 answer:
Misha Larkins [42]3 years ago
4 0

Answer:

The average loss for this device is $10.90

Explanation:

Given data

Specification = 24 +/- 0.4 Amps

average quality cost = $32.00

average value y = 23.9

standard deviation s = 0.211 Amps

32 = k(24.4 - 24)²

32 = k(0.4)² = k(0.16)

k = 32/0.16 = 200

To evaluate average loss, use

L = k{s² + (y - T)²}

T = 24A

L = 200{0.211² + (23.9 - 24)²}

L = $10.90

The average loss for this device is $10.90

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State two main consumers of electricity transmitted at low frequency Calculate the primary voltage of a transformer if the prima
bagirrra123 [75]

Answer:

1) a. Customers requiring AC electric power transmission for powering remote devices which may include a subsea transmission system where power is distributed to subsea devices

b. Customers that utilize commutator-type motors

2) The primary voltage is 150 volts

Explanation:

The parameters given are;

Number of primary winding, N_p = 50 turns

Number of secondary winding, N_s = 150 turns

Voltage in secondary winding, V_s = 450 volts

Voltage in primary winding = V_p

The relation between N_p, N_s, V_s and V_p is as follows;

\dfrac{V_p}{V_s}  = \dfrac{N_p}{N_s}

Which gives;

V_p  = \dfrac{N_p \times V_s}{N_s}

From which we have;

V_p  = \dfrac{50\times 450}{150} = 150 \ volts

The primary voltage = 150 volts.

7 0
3 years ago
Read 2 more answers
A mass of 7 kg undergoes a process during which there is heat transler frorn the mass at a rate of 2 kJ per kg, an elevation dec
irinina [24]

Answer:44.61 KJ

Explanation:

Let h_1,V_1,Z_1 be the initial specific enthalpy,velocity&elevation of the system

and h_2,V_2,Z_2 be the Final specific enthalpy,velocity&elevation of the system

mass(m)=7kg

Applying Steady Flow Energy Equation

m\left [ h_1+\frac{v_1^2}{2g}+gZ_1\right ]+Q=\left [ h_2+\frac{v_2^2}{2g}+gZ_2\right ]+W

h_1-h_2=4 KJ/kg

V_1=13m/s

V_2=23m/s

Z_1-Z_2=40m

substituting values

7\left [ h_1+\frac{13^{2}}{2g}+gZ_1\right ]+7\times2 = \left [ h_2+\frac{23^2}{2g}+gZ_2\right ]+W

W=7\left [h_1-h_2+\frac{V_1^2-V_2^2}{2000g}+g\frac{\left (Z_1-Z_2 \right )}{1000}\right ]+Q

W=7\left [4+\frac{13^2-23^2}{2000g}+g\frac{\left (40 \right )}{1000}[\right ]+2\times 7

W=44.61KJ

4 0
3 years ago
Consider the null-type Wheatstone bridge. Suppose 3 4 R R =   =   100 2 , 200 2 , R2 is variable calibrated resistor, and 1
Lilit [14]

Answer:

Means of R2 is 200 ohms

The uncertainty is 8

Explanation:

Firstly, please check the first attachment for the complete version of the question including the diagram of the Wheatstone bridge. Thanks!

In this question, we are asked to calculate the means of the resistor R2 and its uncertainty required to balance the bridge.

Please check attachment for complete solution.

4 0
3 years ago
Which section(s) of the Code emphasize the fact that all circuiting must be done so as to avoid the damaging effects of inductio
kicyunya [14]

The section(s) of the Code emphasize that all circuiting must be done so as to avoid the damaging effects of induction heating is 300.35, 300.3(B), and 300.20(A).

<h3>What is induction heating?</h3>

The term induction heating is known to be a form of heating of material that occurs via an electric current that makes a flow via the material or its container through the means of electromagnetic induction.

Hence, The section(s) of the Code emphasize that all circuiting must be done so as to avoid the damaging effects of induction heating is 300.35, 300.3(B), and 300.20(A).

Learn more about heating from

brainly.com/question/13982702

#SPJ1

8 0
2 years ago
Points for freeeeeeeeeeeeeee
serg [7]
Thanks for the points.
6 0
2 years ago
Read 2 more answers
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