A chair of weight 95.0N lies atop a horizontal floor; the floor is not frictionless. You push on the chair with a force of F = 3
9.0N directed at an angle of 37.0 degrees below the horizontal and the chair slides along the floor.
1)Using Newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.
1)Using Newton's laws, calculate n, the magnitude of the normal force that the floor exerts on the chair.
2 answers:
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Answer:
The fraction of kinetic energy lost in the collision in term of the initial energy is 0.49.
Explanation:
As the final and initial velocities are known it is possible then the kinetic energy is possible to calculate for each instant.
By definition, the kinetic energy is:
k = 0.5*mV^2
Expressing the initial and final kinetic energy for cars A and B:
Since the masses are equals:
For the known velocities, the kinetics energies result:
The lost energy in the collision is the difference between the initial and final kinectic energies:
Finally the relation between the lost and the initial kinetic energy: