Answer:

Solution:
As per the question:
Mass of first object, m = 120 kg
Mass of second object, m' = 420 kg
Mass of the third object, M = 69.0 kg
Distance between the m and m', d = 0.380 m
Now,
To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m:
To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m':
To calculate the gravitational force on the object of mass, M placed mid-way due to mass, m and m':


Answer:
The girl exerts more pressure.
Explanation:
Pressure can be defined as the force exerted normally or perpendicularly per unit area.
i.e P = F/A
<u>Girls</u>
Area of the heel = 1cm² = 10^(-4) m²
Force = mg = 50 × 10 = 500N
Pressure =


<u>Elephant</u>
<u>Area</u><u> </u><u>=</u><u> </u><u>2</u><u>5</u><u>0</u><u>cm</u><u>²</u><u> </u><u>=</u><u> </u><u>2</u><u>.</u><u>5</u><u> </u><u>x</u><u> </u><u>1</u><u>0</u><u>^</u><u>(</u><u>-</u><u>2</u><u>)</u><u>b</u><u> </u><u>m</u><u>²</u>
<u>Force</u><u> </u><u>=</u><u> </u><u>mg</u><u> </u><u>=</u><u> </u><u>4</u><u>0</u><u>0</u><u>0</u><u>0</u><u>N</u>
<u>Pressure</u><u> </u><u>=</u><u> </u>
<u>
</u>
<u>
</u>
Answer:
raise it as high as he can
Explanation: