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Bezzdna [24]
2 years ago
12

HELP 20 points!

Chemistry
1 answer:
monitta2 years ago
5 0

Answer:

The limiting reagent is the reactant that is completely used up in a reaction, and thus determines when the reaction stops. ... The limiting reagent is the one that is totally consumed; it limits the reaction from continuing because there is none left to react with the in-excess reactant.

Explanation:

The limiting reagent is the reactant that is completely used up in a reaction, and thus determines when the reaction stops. ... The limiting reagent is the one that is totally consumed; it limits the reaction from continuing because there is none left to react with the in-excess reactant.

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For the reaction between aqueous solutions of acetic acid (CH3COOH) and barium hydroxide, Ba(OH)2, 1. Write the balanced molecul
Crazy boy [7]

Answer:

2CH_3COOH(aq)+Ba(OH)_2(aq)\rightarrow Ba(CH_3COO)_2(aq)+2H_2O(l)

Explanation:

When acetic acid solution and barium hydroxide solution react together to give an aqueous solution of barium acetate and water

The balanced chemical reaction will be given by

2CH_3COOH(aq)+Ba(OH)_2(aq)\rightarrow Ba(CH_3COO)_2(aq)+2H_2O(l)

8 0
3 years ago
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salantis [7]

Answer:

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Explanation:

5 0
3 years ago
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What is the ph of a solution with [h+] = 2.3 10-9?
oksano4ka [1.4K]
pH = -log[H+] = -log[2.3*10^-9] = 8.64
8 0
3 years ago
Iodine, I2, is a solid at room temperature but sublimes (converts from a solid into a gas) when warmed. What is the temperature
Stels [109]
<h3>Answer:</h3>

382.63 K

<h3>Explanation:</h3>

We are given;

  • Volume of Iodine as 71.4 mL
  • Mass of Iodine as 0.276 g
  • Pressure of Iodine as 0.478 atm

We are required to calculate the temperature of Iodine

  • We are going to use the ideal gas equation;
  • According to the ideal gas equation; PV = nRT, where R is the ideal gas constant, 0.082057 L.atm/mol.K.
  • Rearranging the formula;

T = PV ÷ nR

But, n, the number of moles = Mass ÷ Molar mass

Molar mass of iodine = 253.8089 g/mol

Thus, n = 0.276 g ÷ 253.8089 g/mol

           = 0.001087 moles

Therefore;

T = (0.478 atm × 0.0714 L) ÷ (0.001087 moles × 0.082057)

  = 382.63 K

Thus, the temperature of Iodine in Kelvin is 382.63 K

3 0
3 years ago
All elements can be classified as metals, metalloids, or ?
svlad2 [7]
All elements can be classified as metals, metalloids, or nonmetals
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3 years ago
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