2 years ago

What is the IMA of the following pulley system?2453

Chemistry

1 answer:

leva [86]2 years ago

5 0

In the pulley system diagram there are 5 ropes. The answer is 5.

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Can anyone help me on this ques pls, much appreaciated

Sloan [31]

Answer:

Option D is Correct answer

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2 years ago

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The mass of sample A is 100.0 g, then removed it from a graduated

yan [13]

Answer: 25g/ml

Explanation:

Density = 100.0g/ 4.0mL = 25g/mL

3 0

3 years ago

Which of the following methods can be used to completely separate a solution containing alcohol and water?

Alenkinab [10]

A only gets out some of it but not all
C that isn't for alcaholl
D I don't think that even exists
B is the only correct answer

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3 years ago

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A car is traveling 50m/s N on the way home. There was an accident and the car slowed to 10m/s for 10secs What is the car's accel

Brilliant_brown [7]

Answer:

4m/s^2

Explanation:

Acc. = final velocity - initial velocity / time taken

= 50 - 10 / 10

= 40/10 = 4ms^2

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2 years ago

what is the minimum mass of ethylene glycol that must be dissolved in 14.5 kg of water to prevent the solution from freexing at

lbvjy [14]

Answer:

The minimum mass of ethylene glycol = 6.641 Kg

Explanation:

$\Delta T_f= T_f-T_f'\\T_f'=T_f-\Delta T_f$

Where T_f = freezing point of pure solvent water, 0°C

T_f'= Freezing point of solvent after mixture

K_f = Freezing point depression constant = 1.86 °C/m

Moecular weight of ethylene glycol = 60 g/mol

Weight of ethylene glycol = 14.5 Kg= 14.5×10^3 g

molality of ethylene glycol

$m = \frac{weight}{mol.wt} \times\frac{1000}{V}$

Substitute the values to calculate m

$m = \frac{w}{60} \times\frac{1000}{14.5\times1000}$

by formula

$0-(-14.2) =1.86\frac{w}{60} \times\frac{1000}{14.5\times1000}$

calculating we get w = 6641.93 g

Therefore, The minimum mass of ethylene glycol = 6.641 Kg

4 0

2 years ago