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3 years ago

Jessica shoebox is 20 cm long and 10 cm wide. How many more millimetres is the length of the shoebox than the width?

1 answer:

8 0

Ok so for every 1 centimeter you get 10 millimeters. Meaning that if you multiply 20 * 10 you get 200 millimeters and if you multiply 10 * 10 you get 100. Now you subtract 200-100 and you get 100 millimeters.

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Could u help me <br><br>with this

AleksandrR [38]

Answer:

P = 7

Step-by-step explanation:

46+8=54

54-5=49

49÷7=P

5 0

3 years ago

Change each of the following points from rectangular coordinates to spherical coordinates and to cylindrical coordinates.

FromTheMoon [43]

Answer and Step-by-step explanation: Spherical coordinate describes a location of a point in space: one distance (ρ) and two angles (Ф,θ).To transform cartesian coordinates into spherical coordinates:

$\rho = \sqrt{x^{2}+y^{2}+z^{2}}$

$\phi = cos^{-1}\frac{z}{\rho}$

For angle θ:

If x > 0 and y > 0: $\theta = tan^{-1}\frac{y}{x}$ ;

If x < 0: $\theta = \pi + tan^{-1}\frac{y}{x}$ ;
If x > 0 and y < 0: $\theta = 2\pi + tan^{-1}\frac{y}{x}$ ;

Calculating:

a) (4,2,-4)

$\rho = \sqrt{4^{2}+2^{2}+(-4)^{2}}$ = 6

$\phi = cos^{-1}(\frac{-4}{6})$

$\phi = cos^{-1}(\frac{-2}{3})$

For θ, choose 1st option:

$\theta = tan^{-1}(\frac{2}{4})$

$\theta = tan^{-1}(\frac{1}{2})$

b) (0,8,15)

$\rho = \sqrt{0^{2}+8^{2}+(15)^{2}}$ = 17

$\phi = cos^{-1}(\frac{15}{17})$

$\theta = tan^{-1}\frac{y}{x}$

The angle θ gives a tangent that doesn't exist. Analysing table of sine, cosine and tangent: θ = $\frac{\pi}{2}$

c) (√2,1,1)

$\rho = \sqrt{(\sqrt{2} )^{2}+1^{2}+1^{2}}$ = 2

$\phi = cos^{-1}(\frac{1}{2})$

$\phi$ = $\frac{\pi}{3}$

$\theta = tan^{-1}\frac{1}{\sqrt{2} }$

d) (−2√3,−2,3)

$\rho = \sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}+3^{2}}$ = 5

$\phi = cos^{-1}(\frac{3}{5})$

Since x < 0, use 2nd option:

$\theta = \pi + tan^{-1}\frac{1}{\sqrt{3} }$

$\theta = \pi + \frac{\pi}{6}$

$\theta = \frac{7\pi}{6}$

Cilindrical coordinate describes a 3 dimension space: 2 distances (r and z) and 1 angle (θ). To express cartesian coordinates into cilindrical:

$r=\sqrt{x^{2}+y^{2}}$

Angle θ is the same as spherical coordinate;

z = z

Calculating:

a) (4,2,-4)

$r=\sqrt{4^{2}+2^{2}}$ = $\sqrt{20}$

$\theta = tan^{-1}\frac{1}{2}$

z = -4

b) (0, 8, 15)

$r=\sqrt{0^{2}+8^{2}}$ = 8

$\theta = \frac{\pi}{2}$

z = 15

c) (√2,1,1)

$r=\sqrt{(\sqrt{2} )^{2}+1^{2}}$ = $\sqrt{3}$

$\theta = \frac{\pi}{3}$

z = 1

d) (−2√3,−2,3)

$r=\sqrt{(-2\sqrt{3} )^{2}+(-2)^{2}}$ = 4

$\theta = \frac{7\pi}{6}$

z = 3

5 0

3 years ago

The value in dollars v(x), of a certain truck after x years is represented by the equation v(x)= 32,500(0.92) raised to the x po

s2008m [1.1K]

The 32,500 is the original cost of the truck and the (0.92) You take v(x)=32,500(0.92)
and raise that to the 2nd power, to represent the 2nd year and you will get an answer of $27,300.
Each year the truck is losing $2,600 in value, after two years the truck has lost $5,200 in value equalling
= $27,300

8 0

3 years ago

Find the value of n. 4 × 62 = (4 x n) + (4 × 2)

tino4ka555 [31]

The answer is 1000 because 62x4= 248 and then you take 248 and multiply it by 4 and you get 992 then you have to multiply 4x2 which is 8 and then when you add 992+8, you would get 100 ;)

7 0

3 years ago

Read 2 more answers

13 subtracted from a number x

Nesterboy [21]

13-x = 13- x
theres is no answer for that x its a variable and 13 is a constant so is just 13-x

6 0

3 years ago

Read 2 more answers